Coordinate Geometry Proofs — Drills

Coordinate Geometry Proofs has 9 drill skills. Each one generates fresh questions every time, with a hint and full worked steps, so you can keep practising a single skill until it settles.

What these drills cover

These questions use 15 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Slope

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Find the slope of the segment from (0, 3) to (7, -5).

Worked answer

-8/7

Rise = -8, run = 7

m = -87

Problem 2

Find the slope of the segment from (3, 0) to (6, 7).

Worked answer

7/3

Rise = 7, run = 3

m = 73

Distance

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Find the length of the segment from (0, 5) to (9, 17).

Worked answer

15

Legs 9 and 12

√81 + 144 = 15

Problem 2

Find the length of the segment from (-2, -1) to (13, 19).

Worked answer

25

Legs 15 and 20

√225 + 400 = 25

Midpoint

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Find the midpoint of (0, 1) and (14, -1).

Worked answer

(7, 0)

x: 0 + 142 = 7

y: 1 + (-1)2 = 0

Problem 2

Find the midpoint of (5, -2) and (13, -10).

Worked answer

(9, -6)

x: 5 + 132 = 9

y: -2 + (-10)2 = -6

Perpendicular lines

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

A line has slope -87. What slope is perpendicular to it?

Worked answer

7/8

Reciprocal: -78

Negated: 78

Check: the product is -1 ✓

Problem 2

A line has slope 13. What slope is perpendicular to it?

Worked answer

-3

Reciprocal: 3

Negated: -3

Check: the product is -1 ✓

Tool

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

You want to prove the shape is a rhombus. Which formula do you use?

Worked answer

distance

"the shape is a rhombus" is a claim about length.

So use the distance formula.

Problem 2

You want to prove two sides are congruent. Which formula do you use?

Worked answer

distance

"two sides are congruent" is a claim about length.

So use the distance formula.

Parallel lines

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Are the segments (5, -1)–(7, 5) and (0, 0)–(2, 6) parallel? Answer yes or no.

Worked answer

yes

First slope: 3

Second slope: 3

Equal, so parallel.

Problem 2

Are the segments (-1, -3)–(1, 5) and (0, 0)–(2, 8) parallel? Answer yes or no.

Worked answer

yes

First slope: 4

Second slope: 4

Equal, so parallel.

Shape

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

A quadrilateral is found to have: opposite sides are parallel and adjacent slopes multiply to -1. Name it.

Worked answer

rectangle

Opposite sides are parallel and adjacent slopes multiply to -1.

That is a rectangle.

Problem 2

A quadrilateral is found to have: exactly one pair of sides has equal slopes. Name it.

Worked answer

trapezoid

Exactly one pair of sides has equal slopes.

That is a trapezoid.

Vertical

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

One side is vertical and the next is horizontal. Are they perpendicular?

  1. Yes, though the slope product rule does not apply
  2. Cannot be determined
  3. No
  4. Only if the lengths match
Worked answer

Yes, though the slope product rule does not apply

They do meet at a right angle.

But a vertical slope is undefined, so m1 m2 = -1 cannot be used — check for vertical sides first.

Proof

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Using convenient coordinates (0,0), (a,0), (a,a), (0,a), prove the diagonals of any square are congruent. Give the common diagonal length.

Worked answer

sqrt(2)a

Compute both diagonals with the distance formula.

Both come to √(2)a.

The letters were never pinned down, so this covers every such shape.

Problem 2

Using convenient coordinates (0,0), (a,0), (a,b), (0,b), prove the diagonals of any rectangle are congruent. Give the common diagonal length.

Worked answer

sqrt(a^2 + b^2)

Compute both diagonals with the distance formula.

Both come to √(a2 + b2).

The letters were never pinned down, so this covers every such shape.

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