Solving Equations & Literal Equations — Drills

Solving Equations & Literal Equations has 6 drill skills. Each one generates fresh questions every time, with a hint and full worked steps, so you can keep practising a single skill until it settles.

What these drills cover

These questions use 3 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Linear

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Solve 7x + 2 = -33.

Worked answer

-5

7x = -35

x = -5

Problem 2

Solve 5x - 12 = -12.

Worked answer

0

5x = 0

x = 0

Variables on both sides

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Solve 7x + 3 = 2x + 48.

Worked answer

9

5x + 3 = 48

5x = 45

x = 9

Problem 2

Solve 6x - 3 = 4x - 15.

Worked answer

-6

2x - 3 = -15

2x = -12

x = -6

Literal

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Solve d = rt for t.

Worked answer

d/r

Divide both sides by r.

t = dr

Problem 2

Solve P = 2l + 2w for w.

Worked answer

(P - 2l)/2

Subtract 2l: P - 2l = 2w

Divide by 2: w = P - 2l2

Fractions

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Solve 5x4 + 3x4 = -96.

Worked answer

-48

× 16: 20x + 12x = -1536

32x = -1536

x = -48

Problem 2

Solve 3x5 + 2x4 = 66.

Worked answer

60

× 20: 12x + 10x = 1320

22x = 1320

x = 60

Special cases

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

Solve 8(x + 6) = 8x + 48. Answer "all" if every value works, or "none" if there is none.

Worked answer

all

8x + 48 = 8x + 48

Subtract 8x: 48 = 48

True, so every value works.

Problem 2

Solve 2(x + 5) = 2x + 16. Answer "all" if every value works, or "none" if there is none.

Worked answer

none

2x + 10 = 2x + 16

Subtract 2x: 10 = 16

False, so no solution.

Word problems

Unlimited questions of this kind are generated in the app. Two examples:

Problem 1

A rectangle has perimeter 110 cm and its length is 9 cm more than its width. Find the width.

Worked answer

23

2w + 2(w + 9) = 110

4w + 18 = 110

4w = 92

w = 23 cm

Problem 2

A rectangle has perimeter 40 cm and its length is 8 cm more than its width. Find the width.

Worked answer

6

2w + 2(w + 8) = 40

4w + 16 = 40

4w = 24

w = 6 cm

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