Physics & Environmental Science — Sample exam worked answers

Student exam paper

A rehearsal paper with separate worked solutions; use it before the final.

22 questions · 44 points · suggested 90 minutes

Student instructions

  1. Suggested time: 90 minutes; allow breaks or accommodations and record them.
  2. Work independently with a calculator, blank paper and the reference relationships printed in this paper. Grades 9, 11 and 12 may also use the course-linked NYSED reference tables. Use no lesson notes or answer key during an assessed attempt.
  3. Show reasoning and units for written tasks. All supplied datasets are illustrative; do not present them as measurements you collected.
  4. Objective items: 1 point each. Written items: 3 points each, one per criterion. A parent or teacher marks the written work; the app never grades an explanation automatically.
  5. Sample exam: try the whole paper before opening the worked key, then revisit the linked chapters. The sample and final are different papers; this is a course assessment, not an official Regents examination.

Reference relationships

Relationship, constant or referenceUse / conditions
ComponentsAx=Acosθ; Ay=Asinθ; θ from +x; use correct quadrant
Constant accelerationv=v₀+at; x−x₀=v₀t+½at²; Constant a only
ForceΣF=ma; weight=mg; Selected object and vector components
Circular accelerationac=v²/r; Inward; supplied by actual interactions
Torqueτ=rFsinθ; Specify pivot and angle
Mechanical energyK=½mv²; Ug=mgh; Us=½kx²; Define height zero and valid spring range
ImpulseJ=Δp=FavgΔt; Vector signs; negligible external impulse for total p conservation
Wavesv=fλ; T=1/f; Medium and mode conditions
Opticsn=c/v; n₁sinθ₁=n₂sinθ₂; Angles from normal
ElectricityI=Q/t; V=IR; P=VI; E=Pt; Ohmic R for V=IR; component values
CapacitorQ=CV; U=½CV²; Linear capacitance model
PhotonE=hf=hc/λ; Kmax=hf−φ; Emission requires threshold energy
Relativityγ=1/√(1−v²/c²); Inertial-frame definitions required
PopulationdN/dt=rN(1−N/K); Instantaneous continuous-model rate
DiversityD=1−Σpi²; State this index convention and sampling
Resource budgetΔstorage=inputs−outputs; Common boundary and interval
Capacity factorEactual/(Prated×time); Not conversion efficiency
NA=6.022×10²³ mol⁻¹Avogadro constant, rounded for school calculations
h=6.626×10⁻³⁴ J·sPlanck constant, rounded
c=3.00×10⁸ m/sVacuum light speed, rounded
e=1.602×10⁻¹⁹ CElementary charge magnitude; 1 eV=1.602×10⁻¹⁹ J
g=9.8 m/s²Typical near-surface Earth approximation; use a supplied local value if given
R=8.314 J/(mol·K)Use SI pressure Pa and volume m³
R=0.0821 L·atm/(mol·K)Use atmosphere pressure and liter volume
F≈96485 C/mol electronsFaraday constant
1 u·c²≈931.5 MeVMass-energy conversion for consistent nuclear mass accounting
T(K)=T(°C)+273.15Use 273 only when a question specifies that rounded convention
1 L=1000 mL; 1 mL=1 cm³Volume conversions
1 kWh=3.60×10⁶ JEnergy conversion
cwater≈4.18 J/(g·°C)Approximate liquid-water specific heat in ordinary conditions
Lf,water≈334 J/g; Lv,water≈2260 J/gWater fusion and vaporization near ordinary-pressure transition conditions

Coverage and marks

ChapterQuestionsPoints
Measurement & Vector Foundations1, 24
Motion & Kinematics3, 44
Forces, Rotation & Equilibrium5, 64
Work, Energy & Momentum7, 84
Waves, Sound & Optics9, 104
Electricity, Magnetism & Circuits11, 124
Modern Physics13, 144
Ecology, Populations & Biodiversity15, 164
Energy, Water & Material Resources17, 184
Pollution, Carbon & Climate Evidence19, 204
Conservation, Systems & Environmental Design21, 224

Parent / teacher marking guide

Question 1 · 1 point

Convert 450 milliseconds to seconds.

Worked answer

0.45 s

450/1000=.450 s.

1 point for the correct objective answer; no written-method marks for this item.

Question 2 · 3 points

A 10N force is 30° above horizontal. Resolve it.

Worked answer

8.66N right,5.00N up

Fx=10cos 30≈8.66.

Fy=10sin 30=5.

Marking criteria

Question 3 · 1 point

A jogger runs 8 km east then 5 km west along one road. What is the magnitude of the displacement?

Worked answer

3 km

Displacement combines opposite directions: 8 − 5 = 3 km east.

1 point for the correct objective answer; no written-method marks for this item.

Question 4 · 3 points

A rock is dropped from rest and falls 44.1 m to the ground. How long does it take — and would a rock launched horizontally from that same height take longer? (g = 9.8 m/s²)

Worked answer

3.0 s; no — the horizontally launched rock takes the same 3.0 s

Use 44.1 = ½(9.8)t² = 4.9t².

t² = 44.1 ÷ 4.9 = 9.0, so t = 3.0 s.

Because vertical motion is independent of horizontal motion, a horizontally launched rock falls in the same 3.0 s — its sideways speed doesn't change the timing.

Marking criteria

Question 5 · 1 point

A club strikes a 0.045 kg golf ball, giving it an acceleration of 2,000 m/s². What net force did the club apply?

Worked answer

90 N

ΣF = ma = 0.045 × 2,000 = 90 N.

1 point for the correct objective answer; no written-method marks for this item.

Question 6 · 3 points

A 6N load at .20 m balances an input at .60 m on the other side. Find input.

Worked answer

2N, neglecting lever mass.

Equal opposite torques:6(.20)=F(.60).

F=1.20/.60.

Marking criteria

Question 7 · 1 point

A crane lifts a 150 kg steel beam 8.0 m upward at constant speed. How much work does it do against gravity? (g = 9.8 m/s²)

Worked answer

11760 J

The lifting force equals the weight, mg = 150 × 9.8 = 1,470 N. W = Fd = 1,470 × 8.0 = 11,760 J.

1 point for the correct objective answer; no written-method marks for this item.

Question 8 · 3 points

A 2N·s impulse acts over .010 s versus .100 s. Compare average forces.

Worked answer

A tenfold longer time gives one-tenth the average force.

Favg=J/Δt.

2/.010=200N and 2/.100=20N.

Marking criteria

Question 9 · 1 point

A wave has a period of 0.004 s. Find its frequency.

Worked answer

250 Hz

f = 1 ÷ T = 1 ÷ 0.004 = 250 Hz.

1 point for the correct objective answer; no written-method marks for this item.

Question 10 · 3 points

Same source recedes.

Worked answer

566.7 Hz

fobs=600×340/(340+20).

204000/360.

Marking criteria

Question 11 · 1 point

A charge of 2 μC (2 × 10⁻⁶ C) sits at a point where it feels an electric force of 0.1 N. Find the electric field strength there.

Worked answer

50000 N/C

E = F ÷ q = 0.1 ÷ (2 × 10⁻⁶) = 50,000 N/C.

1 point for the correct objective answer; no written-method marks for this item.

Question 12 · 3 points

A paper-model device uses 1.2 kW for 2h at supplied price .20 currency/kWh.

Worked answer

0.48 currency units, excluding other charges.

E=1.2×2=2.4 kWh.

Cost=2.4×.20.

Marking criteria

Question 13 · 1 point

Using hc=1240 eV·nm, find photon energy at 620 nm.

Worked answer

2 eV

1240/620=2.

1 point for the correct objective answer; no written-method marks for this item.

Question 14 · 3 points

A detector gives 120 counts in 60 s; background 30 in 60 s. Estimate net count rate.

Worked answer

1.5 counts/s; statistical and detector limits remain.

Subtract counts 120−30=90.

Divide by 60 s.

Marking criteria

Question 15 · 1 point

A wetland's producers have a GPP of 18,000 kcal/m²/yr and spend 7,000 kcal/m²/yr on respiration. What is the net primary productivity (NPP)?

Worked answer

11000 kcal/m²/yr

NPP = GPP - respiration = 18,000 - 7,000 = 11,000 kcal/m²/yr.

1 point for the correct objective answer; no written-method marks for this item.

Question 16 · 3 points

Counts across three 1 m² quadrats are 4,8,6. Find mean density.

Worked answer

6 individuals/m²; range 4–8.

Total 18 over 3 m².

18/3.

Marking criteria

Question 17 · 1 point

Which fossil fuel typically releases the LEAST carbon dioxide per unit of energy when burned?

  1. Coal
  2. Oil (petroleum)
  3. Natural gas
  4. Peat

Worked answer

Natural gas

Natural gas emits roughly half the CO2 of coal per kilowatt-hour, which is why it is often called a 'cleaner' fossil fuel.

1 point for the correct objective answer; no written-method marks for this item.

Question 18 · 3 points

A2 kW source produces 12 kWh in 24h. Find capacity factor.

Worked answer

0.25 or 25%

Maximum 2×24=48 kWh.

12/48.

Marking criteria

Question 19 · 1 point

Biomagnification refers to the way that

  1. decomposers break pollutants down into harmless molecules
  2. a pollutant spreads evenly through the air until it is harmless
  3. a factory's scrubber removes pollutants before they leave the smokestack
  4. a persistent pollutant becomes more concentrated in organisms at each higher step of a food chain

Worked answer

a persistent pollutant becomes more concentrated in organisms at each higher step of a food chain

Because predators eat many contaminated prey and store rather than excrete the toxin, persistent pollutants grow more concentrated at each higher trophic level.

1 point for the correct objective answer; no written-method marks for this item.

Question 20 · 3 points

Change baseline from 14.0 to 14.2°C for absolute temperature 15.0°C.

Worked answer

Baseline alters offset, not the observation.

Original anomaly=1.0°C.

New anomaly=.8°C.

Underlying temperature is unchanged.

Marking criteria

Question 21 · 1 point

An invasive species is best described as

  1. a non-native species that spreads rapidly in a new area and harms native species
  2. any large predator at the top of a food chain
  3. a native species that has lived in an ecosystem for thousands of years
  4. any species that is currently close to extinction

Worked answer

a non-native species that spreads rapidly in a new area and harms native species

Invasive species are non-natives that, lacking natural predators or competitors in the new range, spread out of control and damage native populations.

1 point for the correct objective answer; no written-method marks for this item.

Question 22 · 3 points

A10W reduction operates 2000h/year. Find saved energy.

Worked answer

20 kWh/year

10W=.010 kW.

.010×2000.

Marking criteria

Revisit the covered chapters

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