Area of Triangles & Quadrilaterals — Print
Every area formula in this unit comes from a rectangle that has been cut up or rearranged.
What the practice questions cover
These questions use 8 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.
- Perimeter — Distance all the way around the outside.
- Area — Space inside, measured in square units.
- Parallel — Same slope, different intercept.
- Parallelogram — A quadrilateral with both pairs of opposite sides parallel.
- Trapezoid — A quadrilateral with exactly one pair of parallel sides.
- Base — Any side of a triangle, chosen as the one to measure from.
- Height — The perpendicular distance from the base to the opposite corner.
- Cubic unit — A cube one unit on every edge.
Draw an 8 by 6 rectangle and cut it corner to corner.
You get two triangles. Slide one on top of the other and they match exactly.
So each triangle is exactly half the rectangle — 24, not something that needs a new idea.
The rectangle had area 48, and the cut divided it into two equal pieces.
That is where 12 bh comes from. Every formula here is a rectangle in disguise, which is why you can rebuild any of them from a picture.
Triangles are half a rectangle
Area = 12 bh. The height must be perpendicular to the base, not along a slanted side.
For a right triangle the two legs are the base and height, which is why those are easiest.
For a slanted triangle the height is measured straight down, sometimes landing outside the shape.
Slant is not height
A triangle with sides 5, 5 and base 6 has height 4, not 5. Using a slanted side gives an area that is too big every time.
Parallelograms
Area = bh, with no half. Cut the triangle off one end and slide it to the other, and you have a rectangle.
Nothing was added or removed, so the area never changed.
Again the height is perpendicular, not the slanted side.
Why there is no half here
A parallelogram is the rectangle, rearranged. A triangle is only half of one, which is where the 12 comes from.
Trapezoids
Area = (b1+b2)2 × h — the average of the two parallel sides, times the height.
Put two identical trapezoids together, one upside down, and they form a parallelogram of base b1+b2.
Half of that is one trapezoid, which is exactly the formula.
Average the parallel sides
If the bases were equal it would be a parallelogram, and the average would just be that base. The formula agrees.
Composite shapes
Cut an awkward shape into rectangles and triangles, find each area, and add them up.
Or find the area of a large rectangle and subtract the pieces that are missing.
Either route works; pick whichever needs fewer measurements.
Mark the pieces on the drawing
Draw the cutting lines and label each piece before calculating. Most errors here are pieces counted twice or forgotten.
Units of area
Area is always in square units: square centimetres, square feet, square metres.
That is because you are counting how many unit squares fit inside.
Perimeter, by contrast, is a length, so it is measured in ordinary units.
Squared, not doubled
An answer of "24 cm" for an area is wrong; it is 24 cm². The little two is part of the answer.
Worked examples
A triangle
Find the area of a triangle with base 10 cm and height 6 cm.
- Area = 12 bh. Half the surrounding rectangle.
- = 12 × 10 × 6. Substitute.
- = 30 cm². The rectangle would have been 60 cm².
30 cm²
A trapezoid
Find the area of a trapezoid with parallel sides 8 and 14 and height 5.
- Average the parallel sides: 8+142 = 11. The formula is an average times a height.
- Multiply by the height: 11 × 5. As if it were a rectangle 11 wide.
- = 55 square units. Between 8 × 5 and 14 × 5, as it should be.
55
A composite shape
An L-shape is a 10 by 8 rectangle with a 4 by 3 corner removed. Find its area.
- Whole rectangle: 10 × 8 = 80. Start with the shape it came from.
- Missing corner: 4 × 3 = 12. The piece taken away.
- 80 - 12 = 68 square units. Subtracting is easier here than cutting into two pieces.
68
Words to know
- Base
- Any side of a triangle, chosen as the one to measure from.
- Height
- The perpendicular distance from the base to the opposite corner.
- Parallelogram
- A quadrilateral with both pairs of opposite sides parallel.
- Trapezoid
- A quadrilateral with exactly one pair of parallel sides.
- Composite figure
- A shape made by joining simpler ones.
Mistakes to watch for
Using a slanted side as the height. A triangle with base 6 and equal sides 5 has height 4; using 5 gives 15 instead of the correct 12. The height must meet the base at a right angle.
Halving a parallelogram. Its area is bh with no half — it is a whole rectangle rearranged, not half of one.
Adding the parallel sides of a trapezoid without averaging. The formula uses b1+b22; forgetting the division doubles the answer.
Leaving off the square units. Area is counted in unit squares, so the answer is 30 cm², not 30 cm.
Double-counting in a composite shape. Draw the cutting lines and label each piece; overlapping rectangles quietly add the same region twice.
Egyptian surveyors were computing field areas this way four thousand years ago, after the Nile floods erased the boundaries each year.
A triangle’s area depends only on its base and its height, not on how lopsided it is — sliding the top corner sideways changes nothing.
That fact is why a stack of paper stays the same volume however much you push the top sideways.
Problem 1
Find the area of a triangle with base 10 and height 6.
Worked answer
30
12 × 10 × 6 = 30
Problem 2
Find the area of a triangle with base 7 and height 4.
Worked answer
14
14
Problem 3
Find the area of a rectangle 9 by 5.
Worked answer
45
45
Problem 4
Find the area of a parallelogram with base 8 and height 5.
Worked answer
40
8 × 5 = 40
Problem 5
Find the perimeter of a rectangle 9 by 5.
Worked answer
28
2(9)+2(5) = 28
Problem 6
Find the area of a trapezoid with parallel sides 8 and 14 and height 5.
Worked answer
55
8+142 = 11
11 × 5 = 55
Problem 7
Find the area of a trapezoid with parallel sides 6 and 10 and height 4.
Worked answer
32
8 × 4 = 32
Problem 8
A triangle has base 6 and equal sides 5. Its height is 4. Find the area.
Worked answer
12
12 × 6 × 4 = 12
Problem 9
A triangle has area 24 and base 8. Find its height.
Worked answer
6
12 × 8 × h = 24
4h = 24, so h = 6
Problem 10
An L-shape is a 10 by 8 rectangle with a 4 by 3 corner removed. Find its area.
Worked answer
68
80 - 12 = 68
Problem 11
Area is measured in
- square units
- units
- cubic units
- degrees
Worked answer
square units
So the units are squared
Problem 12
A shape is a 6 by 4 rectangle with a triangle of base 6 and height 3 on top. Find the total area.
Worked answer
33
24 + 9 = 33
Problem 13
A parallelogram has area 56 and height 7. Find its base.
Worked answer
8
b = 8
Problem 14
Find the area of a triangle with base 4.5 and height 8.
Worked answer
18
12 × 4.5 × 8 = 18
Problem 15
A rectangle 12 by 5 has a 3 by 3 square cut from one corner. Find the remaining area.
Worked answer
51
60 - 9 = 51
Problem 16
A trapezoid has area 45, height 5 and one parallel side 7. Find the other.
Worked answer
11
7+b2 × 5 = 45
7+b2 = 9, so b = 11