Problem Solving — Challenge

A hard problem is rarely beaten by cleverness. It is beaten by a method: understand it, pick a strategy, carry it out, then check.

What these problems cover

These questions use 6 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Problem 1

A cinema sells adult tickets at $12 and child tickets at $8. What is the cost in dollars for two adults and three children?

  1. $40
  2. $44
  3. $48
  4. $52
  5. $60
Worked answer

$48

Two adults cost 2· 12 = 24 dollars.

Three children cost 3· 8 = 24 dollars.

The total is 24+24 = 48 dollars.

Problem 2

A gardener plants trees in a straight line, 4 metres apart. The first and last trees are 36 metres apart. How many trees are there?

  1. 8
  2. 9
  3. 10
  4. 11
  5. 36
Worked answer

10

The gaps between the trees number 364 = 9.

A line of trees has one more tree than it has gaps, like fence posts along a fence.

So there are 9+1 = 10 trees. Answering 9 counts the gaps rather than the trees.

Problem 3

A shop sells pens only in packs of 5 and packs of 8. What is the largest number of pens that cannot be bought exactly?

  1. 19
  2. 22
  3. 25
  4. 27
  5. 35
Worked answer

27

A total is possible when it can be written as 5a+8b for whole numbers a and b.

Once five consecutive totals are possible, so is every larger one, because adding another pack of 5 steps forward from one of them.

The run 28,29,30,31,32 is possible: 28=5· 4+8, 29=5+8· 3, 30=5· 6, 31=5· 3+8· 2 and 32=8· 4.

Checking downwards, 27 cannot be made: 27-8=19, 27-16=11 and 27-24=3 are none of them multiples of 5. So 27 is the largest impossible total.

Problem 4

A bus holds 45 passengers. How many buses are needed to carry 200 passengers?

  1. 4
  2. 4.4
  3. 5
  4. 6
  5. 45
Worked answer

5

20045≈ 4.44, so four buses are not enough.

Four buses carry 180 passengers, leaving 20 still to travel, who need a fifth bus.

The answer must be a whole number of buses, so 5.

Problem 5

The sum of three consecutive even numbers is 42. What is the largest of them?

  1. 12
  2. 14
  3. 16
  4. 18
  5. 20
Worked answer

16

Call the middle number n, so the three numbers are n-2, n and n+2.

Their sum is 3n = 42, so n = 14 and the numbers are 12, 14 and 16.

The largest is 16.

Problem 6

A rope 24 metres long is cut into pieces 3 metres long. How many pieces are there?

  1. 6
  2. 7
  3. 8
  4. 9
  5. 72
Worked answer

8

Divide the whole length by the length of one piece.

243 = 8 pieces.

Problem 7

A worker is paid $18 an hour for the first 40 hours and $27 an hour after that. What is the pay in dollars for a 46-hour week?

  1. $828
  2. $862
  3. $882
  4. $1,242
  5. $720
Worked answer

$882

The first 40 hours pay 40· 18 = 720 dollars.

The remaining 6 hours pay 6· 27 = 162 dollars.

The total is 720+162 = 882 dollars.

Problem 8

Two taps together fill a tank in 6 hours. One of them alone would take 10 hours. How many hours would the other take alone?

  1. 4
  2. 8
  3. 12
  4. 15
  5. 16
Worked answer

15

Together the taps fill 16 of the tank each hour, and the slow one fills 110.

The other fills 16-110 = 530-330 = 230 = 115 each hour.

Filling one fifteenth each hour means it takes 15 hours alone.

Problem 9

A number is doubled, then 7 is subtracted, giving 23. What was the number?

  1. 8
  2. 12
  3. 15
  4. 16
  5. 30
Worked answer

15

Work backwards. Before subtracting 7 the value was 23+7 = 30.

That was the number doubled, so the number itself is 302 = 15.

Check: 15 doubled is 30, and 30-7 = 23.

Problem 10

Tickets cost $9 each. A group pays $135 in total. How many tickets did they buy?

  1. 12
  2. 13
  3. 14
  4. 15
  5. 16
Worked answer

15

Divide the total paid by the price of one ticket.

1359 = 15 tickets.

Check: 15· 9 = 135.

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