Lewis Structures, Resonance & Bond Models · Grade 11 Science

Chapter: Bonding, Formulas & Molecular Structure

Lewis Structures, Resonance & Bond Models

Learning goals

Readings for this unit

Before this unit

Valence electrons, ionic charge, and covalent bonding.

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Start with something to explain

Do two resonance drawings show a molecule changing back and forth?

Illustrative evidence case. Two ozone contributors place the formal double bond on opposite sides without moving atoms.

Start a Lewis structure with an explicit electron budgetStart a Lewis structure with an explicit electron budgetCO₂: 4 + 2(6) = 16 valence electrons8 electrons in bonds + 8 as lone pairs = 16Count all displayed electrons, including charge adjustments.OCO
Original CO₂ Lewis inventory. Dot locations are symbolic lone-pair assignments, not stationary electron coordinates.

Notice and wonder

Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.

Do two resonance drawings show a molecule changing back and forth?

Your first model

Keep atom positions fixed and track only electron assignments.

Build the language from the idea

lone pair
A valence electron pair not represented as a bond.
formal charge
An electron-counting assignment, distinct from partial charge.
resonance
Multiple electron drawings representing delocalized bonding in one structure.

A Lewis structure is a model of valence electrons: dots represent lone electrons and lines represent shared pairs. Count all valence electrons first; add electrons for negative charge and subtract for positive charge. Identify a central atom, usually a less electronegative non-hydrogen atom, and connect terminal atoms with single bonds.

Start a Lewis structure with an explicit electron budgetStart a Lewis structure with an explicit electron budgetCO₂: 4 + 2(6) = 16 valence electrons8 electrons in bonds + 8 as lone pairs = 16Count all displayed electrons, including charge adjustments.OCO
Original CO₂ Lewis inventory. Dot locations are symbolic lone-pair assignments, not stationary electron coordinates.

Distribute remaining electrons to complete terminal octets, with hydrogen needing only two. Put leftovers on the central atom; if its octet is incomplete, consider a double or triple bond. Recount electrons. This procedure explains CO₂ with two double bonds and H₂O with two O–H bonds and two lone pairs on oxygen.

The octet rule is a useful pattern, not a universal law. Hydrogen follows a duet; boron compounds can have incomplete octets; odd-electron molecules exist; some third-period and heavier atom structures are conventionally drawn with expanded valence shells. A model should be applied within its scope.

The octet rule is an approximation, not a universal physical commandThe octet rule is an approximation, not a universal physical commandSpeciesValence electronsOctet-related featureCH₄8C has an octetBF₃24B has six around itNO11Odd-electron speciesSF₆48Expanded Lewis accountingThe octet rule is a useful pattern with a defined scope.
Original selected electron totals and exception categories; formulas are examples, not instructions for synthesizing hazardous substances.

Formal charge is bookkeeping: valence electrons minus nonbonding electrons minus half of bonding electrons. It is not the same as measured partial charge. For NH₄⁺, nitrogen has 5 − 0 − 4 = +1 and each hydrogen has 0 formal charge; the total is +1.

Formal charge is a specified electron-assignment conventionFormal charge is a specified electron-assignment conventionFormal charge = valence − nonbonding − ½(bonding)NH₄⁺: N = 5 − 0 − 4 = +1; each H = 0NHHHH
Original ammonium Lewis bookkeeping. The flat cross shows connectivity only, not the molecule’s tetrahedral geometry.

Resonance structures use the same atom arrangement but different electron placement. The actual bonding is described by a delocalized structure, not a molecule rapidly switching between drawings. In nitrate, three equivalent N–O arrangements contribute; the real bonds are equivalent in the idealized ion.

Resonance drawings represent one delocalized electronic structureResonance drawings represent one delocalized electronic structureO=O⁺–O⁻⁻O–O⁺=OSame atom connectivity; different electron assignmentsOne delocalized structure, not rapid switching between drawingsThe two O–O bonds are equivalent in the ideal isolated molecule.
Original compact ozone resonance notation. Lone pairs are omitted from this shorthand and must be restored for a complete eighteen-electron Lewis count.

Use Lewis structure to count electron domains before predicting shape with VSEPR. A double bond counts as one direction of electron density. Separate electron-domain geometry from molecular shape, because lone pairs also occupy domains. Molecular polarity depends on the vector sum of bond dipoles and geometry.

Build your understanding

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Part 1 · Count valence electrons including charge

A Lewis structure tracks valence-electron pairs and atom connectivity. Add the valence electrons from all atoms, then add electrons for negative charge or subtract them for positive charge. In CO₂ the total is sixteen: eight in two double bonds and eight as oxygen lone pairs. A line represents two electrons, while a dot represents one. Counting the whole drawing prevents plausible-looking structures that secretly create or omit electrons; it is a model of valence bookkeeping, not a complete electron-density map.

Start a Lewis structure with an explicit electron budgetStart a Lewis structure with an explicit electron budgetCO₂: 4 + 2(6) = 16 valence electrons8 electrons in bonds + 8 as lone pairs = 16Count all displayed electrons, including charge adjustments.OCO
Original CO₂ Lewis inventory. Dot locations are symbolic lone-pair assignments, not stationary electron coordinates.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

How many lone-pair electrons are shown in the CO₂ structure after its bonding electrons are counted?

Visual reasoning — after your attempt

Eight lone-pair electrons remain after eight of the sixteen are assigned to the two double bonds.

Add valence electrons from each atom, add electrons for negative charge, and subtract for positive charge. Start a reasonable skeleton using supplied connectivity, then distribute electrons while tracking the total. A Lewis structure is an electron-bookkeeping model, not a complete image of quantum electron density.

CO₃²⁻ has 4+3×6+2=24 valence electrons. Ignoring the 2− charge leaves the wrong total and can produce an inconsistent diagram.

Pause and explain

Why does a negative charge increase the valence-electron total?

Check your reasoning after answering

The ion has gained electrons relative to the neutral atom total. Each unit of negative charge adds one electron to the bookkeeping.

Part 2 · Use octets with known exceptions

The octet rule is a useful pattern for many main-group Lewis structures, especially common second-period compounds. It has important exceptions: hydrogen uses a duet, some species are electron-deficient, some have an odd electron, and heavier-element Lewis accounts can assign more than eight electrons around a center. These patterns do not mean atoms consciously seek an octet. Advanced bonding models refine the interpretation of hypervalent species rather than simply proving that empty d orbitals act as storage boxes.

The octet rule is an approximation, not a universal physical commandThe octet rule is an approximation, not a universal physical commandSpeciesValence electronsOctet-related featureCH₄8C has an octetBF₃24B has six around itNO11Odd-electron speciesSF₆48Expanded Lewis accountingThe octet rule is a useful pattern with a defined scope.
Original selected electron totals and exception categories; formulas are examples, not instructions for synthesizing hazardous substances.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

Why is an eleven-valence-electron molecule a warning against requiring paired octets everywhere?

Visual reasoning — after your attempt

An odd total cannot be distributed exclusively into paired electron groups; an odd-electron model or a different species assignment must be considered.

For many main-group examples, octets help guide electron placement after bonding and lone pairs are assigned. Hydrogen uses a two-electron arrangement. Electron-deficient species, odd-electron species, and some heavier-element representations require exceptions. Do not force a wrong electron total merely to draw every atom with eight.

NH₄⁺ has four N–H bonds and no nitrogen lone pair in its introductory structure. The charge and hydrogen duet rule are essential to checking the total.

Pause and explain

Should an octet rule override the supplied electron count?

Check your reasoning after answering

No. Keep the correct total and recognize known exceptions. An octet is a useful pattern for many cases, not an unconditional command.

Part 3 · Use formal charge as bookkeeping

Formal charge assigns bonding electrons equally between bonded atoms: valence count minus nonbonding electrons minus half the bonding electrons. In NH₄⁺, nitrogen has four single bonds and no lone pair, giving formal charge +1; each hydrogen has zero. The sum must equal the species’ net charge. Formal charge helps compare Lewis candidates but is not a direct measurement of actual partial charge, and it is distinct from oxidation-number bookkeeping, which assigns bonding electrons differently.

Formal charge is a specified electron-assignment conventionFormal charge is a specified electron-assignment conventionFormal charge = valence − nonbonding − ½(bonding)NH₄⁺: N = 5 − 0 − 4 = +1; each H = 0NHHHH
Original ammonium Lewis bookkeeping. The flat cross shows connectivity only, not the molecule’s tetrahedral geometry.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

Why must the formal charges in a complete NH₄⁺ drawing sum to +1?

Visual reasoning — after your attempt

The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.

Formal charge=valence count−nonbonding electrons−half bonding electrons. The formal charges sum to the total ion charge. This assignment is not identical to measured partial charge or oxidation number. It helps compare plausible Lewis representations when combined with connectivity and chemical evidence.

An oxygen with three lone pairs and one single bond has formal charge 6−6−1=−1. An oxygen with two lone pairs and a double bond has formal charge zero.

Pause and explain

Is formal charge the actual localized physical charge on an atom?

Check your reasoning after answering

Not exactly. It is an equal-sharing bookkeeping assignment; actual electron density and partial charges can be distributed differently.

Part 4 · Interpret resonance as one delocalized structure

Resonance contributors keep the same atom connectivity while changing allowed electron assignments. In the selected ozone account, the central oxygen has +1 formal charge and one terminal oxygen −1 in either contributor. The real molecule is not alternately one localized single/double pattern and then the other; it has a delocalized electronic structure. Equivalent contributors support equivalent bond behavior in the ideal symmetric case. Resonance arrows are not ordinary chemical-reaction arrows or movement of atomic nuclei between structures.

Resonance drawings represent one delocalized electronic structureResonance drawings represent one delocalized electronic structureO=O⁺–O⁻⁻O–O⁺=OSame atom connectivity; different electron assignmentsOne delocalized structure, not rapid switching between drawingsThe two O–O bonds are equivalent in the ideal isolated molecule.
Original compact ozone resonance notation. Lone pairs are omitted from this shorthand and must be restored for a complete eighteen-electron Lewis count.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

What stays fixed when moving between these ozone resonance contributors?

Visual reasoning — after your attempt

The three-oxygen connectivity and nuclear arrangement stay fixed; only the formal electron and bond assignments change.

Resonance contributors have the same atom connectivity but different electron placements. The actual structure is not rapidly flipping between separate drawings. Equivalent contributors can represent delocalization and equalized bonds; bond lengths provide evidence that a single localized drawing is incomplete.

Carbonate has three equivalent placements of one drawn C=O bond. The real ion has equivalent C–O bonds in the usual model, rather than one permanently double bond and two permanently single bonds.

Pause and explain

What stays fixed between resonance contributors?

Check your reasoning after answering

Atom connectivity stays fixed while electron placement changes. They represent contributions to one delocalized structure, not different isomers.

Apply the whole unit · Account for carbonate resonance

Illustrative ion CO₃²⁻ has carbon central and three oxygen neighbors. Use C=4 and O=6 valence electrons, and the formal-charge rule supplied in this lesson.

Your task

Count electrons, draw a valid contributor with one double bond, assign formal charges, draw the other equivalent contributors, and explain what equal measured C–O lengths would support.

What your response should show

  • Choose the appropriate chemical model or relationship and state its conditions.
  • Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
  • Use supplied evidence to justify the conclusion; distinguish observation from inference.
  • Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
  1. Count 24 valence electrons.

  2. Use one C=O and two C–O bonds; assign lone pairs to satisfy oxygen octets.

  3. Carbon and double-bonded oxygen have formal charge 0; each single-bonded oxygen has −1.

  4. Move the drawn double bond to each oxygen while keeping connectivity unchanged.

The formal charges total −2 and all 24 electrons are accounted for. Equal C–O lengths support delocalization rather than three permanently unequal localized bonds. Contributors are bookkeeping representations of one ion; they are not atom rearrangements or a movie of the ion switching structures.

Scientific references and source-model foundations

Parent / teacher teaching notes

Check total electrons before judging a diagram. Separate formal charge, oxidation number, and partial charge. Use measured-bond evidence to explain why resonance is needed. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.

Water: bonds, lone pairs, and shapeOHH8 total valence electronsTwo bonding pairs + two lone pairs → bent molecular shape
Water has two oxygen–hydrogen bonds and two oxygen lone pairs. The four electron domains give a bent molecular shape; drawing is schematic.

The key idea

Count electrons and charge before predicting bonding, shape, and polarity.

Worked examples

Example 1

Build the Lewis structure of water.
  1. O contributes 6 electrons and two H contribute 2: total 8.
  2. Two O–H bonds use 4 electrons.
  3. The remaining 4 give two oxygen lone pairs.
Answer: Two bonds and two lone pairs; bent molecular shape.

Example 2 · Worked application

Count valence electrons and draw a Lewis model for CO₂.
  1. Carbon supplies 4 and two oxygens supply 12: total 16.
  2. Place carbon centrally and form two double bonds.
  3. Each oxygen has two lone pairs; count all 16 electrons and check octets.
Answer: O=C=O with two lone pairs on each oxygen.
Check the reasoning

Formal electron counting is a model; resonance is not rapid physical switching.

Example 3

Count valence electrons in CO₃²⁻.
  1. C contributes 4 and three O contribute 18.
  2. Add 2 for the negative charge.
Answer: 24 valence electrons.

Example 4 · Find and fix the mistake

Context: Count valence electrons and draw a Lewis model for CO₂. A student claims: “Resonance means a molecule alternates between separate Lewis drawings.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Formal electron counting is a model; resonance is not rapid physical switching.
  2. Resonance drawings represent contributions to one delocalized electronic structure, not distinct structures flipping back and forth.
Answer: Resonance drawings represent contributions to one delocalized electronic structure, not distinct structures flipping back and forth.
Check the reasoning

Formal electron counting is a model; resonance is not rapid physical switching.

Example 5 · Reason from the visual model

Formal charge is a specified electron-assignment conventionFormal charge is a specified electron-assignment conventionFormal charge = valence − nonbonding − ½(bonding)NH₄⁺: N = 5 − 0 − 4 = +1; each H = 0NHHHH
Original ammonium Lewis bookkeeping. The flat cross shows connectivity only, not the molecule’s tetrahedral geometry.
Why must the formal charges in a complete NH₄⁺ drawing sum to +1?
  1. Formal charge assigns bonding electrons equally between bonded atoms: valence count minus nonbonding electrons minus half the bonding electrons. In NH₄⁺, nitrogen has four single bonds and no lone pair, giving formal charge +1; each hydrogen has zero. The sum must equal the species’ net charge. Formal charge helps compare Lewis candidates but is not a direct measurement of actual partial charge, and it is distinct from oxidation-number bookkeeping, which assigns bonding electrons differently.
  2. The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.
Answer: The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.
Check the reasoning

Original ammonium Lewis bookkeeping. The flat cross shows connectivity only, not the molecule’s tetrahedral geometry.

Avoid these mistakes

Check your understanding

How do you check a proposed Lewis structure?

Discuss the answer

Recount valence electrons, confirm total charge, check bond and lone pairs and applicable octet exceptions, then determine shape.

Return to the phenomenon

Return to the initial case. Do two resonance drawings show a molecule changing back and forth? Revise your drawing or explanation using two named ideas and one stated limitation.

Compare explanations after your attempt

They represent one delocalized structure, not a time sequence of two isolated structures. The model should explain equivalent bond behavior and conserve electron count.

What should we investigate next?

Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.

Investigate, calculate and revise

Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.

Activity 1 · Return to the opening case

Assigned reading and preparation

Use the opening phenomenon, unit definitions and explained Parts 1–4.

Your task

Return to the initial case. Do two resonance drawings show a molecule changing back and forth? Revise your drawing or explanation using two named ideas and one stated limitation.

Success criteria

  • Use the stated observations and appropriate units.
  • Connect a labeled model with the chemical mechanism.
  • State assumptions and an evidence limitation.
  • Explain a substantive revision or next test.
Hint

Keep species identity, material transfer and energy account distinct.

Response guidance — discuss after your attempt

They represent one delocalized structure, not a time sequence of two isolated structures. The model should explain equivalent bond behavior and conserve electron count.

Activity 2 · Transfer to a changed case

Assigned reading and preparation

Cover the worked answer and use the explained models, relationships and notebook.

Your task

For NH₄⁺, count valence electrons, assign nitrogen’s formal charge for four N–H single bonds and no lone pair, and distinguish that charge from molecular shape.

Success criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the chemical mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.
Hint

Name known quantities and conditions, show intermediate steps and check conservation.

Response guidance — discuss after your attempt

Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.

Words to know

lone pair
A valence electron pair not represented as a bond.
formal charge
An electron-counting assignment, distinct from partial charge.
resonance
Multiple electron drawings representing delocalized bonding in one structure.

In the real world

Use the chapter investigation to connect this unit to measured evidence and a practical decision.

Exit check

How do you check a proposed Lewis structure?

Check your explanation after answering

Recount valence electrons, confirm total charge, check bond and lone pairs and applicable octet exceptions, then determine shape.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

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