Calorimetry, Hess’s Law & Enthalpy Calculations — Practice · Grade 11 Science
Chapter: Chemical Energy & ThermodynamicsWhat this practice covers
By the end of Calorimetry, Hess’s Law & Enthalpy Calculations you should be able to:
- I can determine reaction heat from a measured surroundings change with consistent signs.
- I can add thermochemical equations and scale their enthalpy changes.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: calorimeter heat capacity, state function, Hess’s law.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
836 J
50×4.18×4.
Problem 2
Answer and explanation
The same state difference is traversed in the opposite direction.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
836 J
40×4.18×5=836.
Problem 4
Answer and explanation
Less heat reaches the measured solution, so the estimated release magnitude is typically too small.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
System and surroundings have opposite signs in this boundary.
Answer and explanation
−3.5 kJ, assuming no other transfers.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
20−55=−35 kJ by Hess's law with the given orientations and scales.
Problem 7
Answer and explanation
B is an intermediate in the summed transformation. Its associated state-change energy remains part of the overall endpoint balance.
Hess’s law uses the state-function character of enthalpy: the overall change depends on initial and final states rather than which conceptual route is added. Scale or reverse component equations as necessary, cancel shared intermediates and apply the same operations to their enthalpies. Intermediate B can disappear from the net equation without implying it was never involved in a real mechanism. The algebraic route need not be the actual laboratory pathway, and phases must match when canceling a species.
B is an intermediate in the summed transformation. Its associated state-change energy remains part of the overall endpoint balance.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
qwater=50.0×4.18×8.00=1672 J. qreaction≈−1.672 kJ. Dividing by 0.0200 mol gives approximately −83.6 kJ/mol on the specified reacting-amount basis, subject to the neglected terms.
qwater=50.0×4.18×8.00=1672 J. qreaction≈−1.672 kJ. Dividing by 0.0200 mol gives approximately −83.6 kJ/mol on the specified reacting-amount basis, subject to the neglected terms.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.