The Mole & Molar Mass — Practice · Grade 11 Science
Chapter: Reactions, Moles & CompositionWhat this practice covers
By the end of The Mole & Molar Mass you should be able to:
- I can explain what a mole is and why chemists use Avogadro's number to count atoms and molecules.
- I can calculate the molar mass of a compound from atomic masses and convert among mass, moles, and number of particles.
10 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: mole (mol), Avogadro's number, molar mass, atomic mass, representative particle.
Problem 1
Answer and explanation
44.01 g/mol
Molar mass = 12.01 + 2(16.00) = 12.01 + 32.00 = 44.01 g/mol.
Problem 2
- 6.022 × 10²³
- 3.14 × 10⁰
- 1.602 × 10⁻¹⁹
- 9.81 × 10⁰
Answer and explanation
6.022 × 10²³
One mole is defined as 6.022 × 10²³ particles.
Problem 3
Answer and explanation
2 mol
moles = mass ÷ molar mass = 88.02 g ÷ 44.01 g/mol = 2.00 mol.
Problem 4
Answer and explanation
54.06 g
mass = moles × molar mass = 3.00 mol × 18.02 g/mol = 54.06 g.
Problem 5
Answer and explanation
1.2044e+24 molecules
molecules = moles × Avogadro's number = 2.00 × 6.022 × 10²³ = 1.2044 × 10²⁴ molecules.
Problem 6
Answer and explanation
180.18 g/mol
6(12.01) + 12(1.01) + 6(16.00) = 72.06 + 12.12 + 96.00 = 180.18 g/mol.
Problem 7
Hints
Identify the requested entity before applying the mole conversion.
Answer and explanation
11.0/44.0=0.250 mol.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
0.50 mol molecules×2=1.0 mol O atoms, or 6.02×10²³ atoms.
Problem 9
Answer and explanation
The grams would not cancel the mole denominator. First convert mass to moles with the substance’s molar mass.
Convert mass to amount using n=m/Mₘ, then multiply amount by the Avogadro constant to obtain specified-entity count. Each conversion factor must cancel the previous unit and retain the entity name. The selected 18.0 g/mol water value is a rounded school input; using it consistently gives 2.00 mol from 36.0 g and approximately 1.20×10²⁴ water molecules. Mole amount is not itself a mass or volume, so do not skip the chemical composition step.
The grams would not cancel the mole denominator. First convert mass to moles with the substance’s molar mass.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
n=22.0/44.0=0.500 mol CO₂. Molecules≈3.01×10²³. Each has two O atoms, giving 1.00 mol O atoms. Keep the entity labels through every conversion.
n=22.0/44.0=0.500 mol CO₂. Molecules≈3.01×10²³. Each has two O atoms, giving 1.00 mol O atoms. Keep the entity labels through every conversion.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.