Biodiversity & Ecosystem Services — Practice · Grade 12 Science
Chapter: Ecology, Populations & BiodiversityWhat this practice covers
By the end of Biodiversity & Ecosystem Services you should be able to:
- I can distinguish genetic, species, and ecosystem diversity and use a diversity index to compare communities.
- I can explain how biodiversity supports ecosystem services and resilience, and why keystone species matter.
9 questions, multiple choice, numeric and written answer, each with a worked explanation.
Vocabulary used: biodiversity, genetic diversity, species diversity, ecosystem diversity, ecosystem services, keystone species.
Problem 1
- The variety of alleles for coat color within a single wolf population
- The range of ecosystems found across a continent
- The total biomass of producers in a field
- The number of different bird species in a forest
Answer and explanation
The variety of alleles for coat color within a single wolf population
Genetic diversity is variation within a species or population, such as different coat-color alleles in one wolf population.
Problem 2
- Cultural
- Regulating
- Genetic
- Provisioning
Answer and explanation
Regulating
Purifying water is a regulating service — the ecosystem stabilizes and improves environmental conditions.
Problem 3
Answer and explanation
0.42
(0.30)² + (0.70)² = 0.09 + 0.49 = 0.58; D = 1 - 0.58 = 0.42.
Problem 4
- invasive species
- decomposer
- keystone species
- producer at the base of the food web
Answer and explanation
keystone species
Its impact is far greater than its abundance, and its removal reshapes the whole community — the definition of a keystone species.
Problem 5
Answer and explanation
With many different alleles present, it is more likely that at least some individuals happen to carry genes that resist the disease. Those individuals survive and reproduce, so the population persists, whereas a genetically uniform population could be wiped out all at once.
Problem 6
Hints
Use a service-specific measure and sampling design.
Answer and explanation
Equal richness can hide strong dominance differences and altered functioning.
Problem 7
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Baseline and comparison data, consistent methods and a mechanism linking restoration to the measured service.
Problem 8
Answer and explanation
D=1−(0.64+0.04)=0.32 under the stated convention.
For this course, the selected Simpson diversity convention is D=1−Σpi², with pi the observed fraction in species i. Larger values mean greater diversity under this convention. Other publications use the sum or its reciprocal, so the name alone is ambiguous. For four equally common species D=0.75. The result is an estimate from sampled counts and does not identify habitat quality, extinction risk or causal mechanisms by itself.
D=1−(0.64+0.04)=0.32 under the stated convention.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 9
Answer and explanation
Richness=3. Fractions 0.6,0.3,0.1 give D=1−(0.36+0.09+0.01)=0.54. The sample may miss rare or hard-to-detect species; matched effort and replication matter.
Richness=3.
Fractions 0.6,0.3,0.1 give D=1−(0.36+0.09+0.01)=0.54.
The sample may miss rare or hard-to-detect species; matched effort and replication matter.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.