Electrical Power, Energy & Circuit Design — Practice · Grade 12 Science
Chapter: Electricity, Magnetism & CircuitsWhat this practice covers
By the end of Electrical Power, Energy & Circuit Design you should be able to:
- I can calculate component power and energy with correct circuit values.
- I can distinguish efficiency, kilowatt-hours, and source internal losses.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: kilowatt-hour, internal resistance, emf.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
1.8 W
P=VI.
Problem 2
Answer and explanation
Energy; it is power multiplied by time.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
0.008 kWh
.004 kW×2h=.008 kWh.
Problem 4
Answer and explanation
Very low external resistance permits large current; internal resistance then dissipates substantial I²r heat.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
Kilowatt-hour is energy, not power per hour.
Answer and explanation
1 kWh, equivalent to 3.6×10⁶ J.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
The 10 W lamp uses less energy per equal operating time; broader impact also requires lifetime and other factors.
Problem 7
Answer and explanation
3 A and 36 W at unchanged 12 V, assuming the source maintains that voltage.
For ideal parallel loads sharing 12 V, source current is the sum of branch currents. Here 2+3+1=6 A and source output power is 72 W. A real source and conductors have operating limits and losses, so an ideal current sum is only part of a design comparison. Consider voltage regulation, continuous versus peak demand and the stated component ratings. Use supplied-data design here rather than modifying household wiring.
3 A and 36 W at unchanged 12 V, assuming the source maintains that voltage.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Saving=(0.015−0.009)×2500=15 kWh=5.40×10⁷ J/year. Production, transport, replacement lifespan or disposal is outside this operational-only result.
Saving=(0.015−0.009)×2500=15 kWh=5.40×10⁷ J/year.
Production, transport, replacement lifespan or disposal is outside this operational-only result.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.