Newton's Three Laws of Motion — Print · Grade 12 Science

Chapter: Forces, Rotation & Equilibrium

Newton's Three Laws of Motion

Learning goals

Readings for this unit

Before this unit

Mass versus weight and signed net force.

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Start with something to explain

Why can a moving cart have zero net force?

Illustrative evidence case. A steady cart is pulled forward while resistance acts backward.

Zero net force allows steady motionZero net force allows steady motionselected bodydrive 8 Ndrag 8 NnormalweightBalanced forces: a=0; velocity may be nonzero.
Original free-body diagram; equal opposing arrow lengths mark balance, not absence of interactions.

Notice and wonder

Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.

Why can a moving cart have zero net force?

Your first model

Name each force’s agent and receiving body.

Build the language from the idea

inertia
The tendency of an object to resist any change in its state of motion; measured by its mass.
Newton's first law
An object at rest stays at rest, and an object in motion stays in motion at constant velocity, unless acted on by a nonzero net force.
Newton's second law
The net force on an object equals its mass times its acceleration: ΣF = ma.
Newton's third law
For every force one object exerts on a second, the second exerts an equal and opposite force back on the first.
newton (N)
The SI unit of force; 1 N is the force that accelerates 1 kg at 1 m/s², so 1 N = 1 kg·m/s².

Newton’s laws describe a powerful model for ordinary macroscopic motion in inertial frames. A force is an interaction that contributes to acceleration through the net-force account. Their range is not literally every physical situation: relativistic speeds, quantum-scale evidence and rotating frames need additional models. Within their useful range, identify the object, interactions, mass and coordinate directions to predict how its velocity changes.

Newton's first law, the law of inertia, states that an object keeps doing whatever it is already doing — sitting still or gliding at constant velocity in a straight line — unless a nonzero net force acts on it. Inertia is simply an object's built-in resistance to any change in its motion, and its mass is the direct measure of that resistance. This law overturned a 2,000-year-old belief, going back to Aristotle, that motion needs a continuous push to keep going. The truth is the reverse: a rolling ball slows only because friction and air resistance push back on it. Remove those forces, as in deep space, and the ball glides on forever with no engine at all.

Zero net force allows steady motionZero net force allows steady motionselected bodydrive 8 Ndrag 8 NnormalweightBalanced forces: a=0; velocity may be nonzero.
Original free-body diagram; equal opposing arrow lengths mark balance, not absence of interactions.

Newton's second law turns that idea into an equation: ΣF = ma, the net force on an object equals its mass times its acceleration. Read carefully, it says two intuitive things at once. First, for a given mass, a larger net force produces a larger acceleration — push harder and it speeds up faster. Second, for a given net force, a larger mass produces a smaller acceleration — that is inertia again. The Greek letter Σ (sigma) means 'sum of,' a crucial reminder that acceleration depends on the *net* force, the single vector left after every push and pull is combined. Force is measured in newtons (N), where one newton accelerates one kilogram at one meter per second squared.

Acceleration uses the sum of forces on one bodyAcceleration uses the sum of forces on one bodyselected body12 N8 Nm = 2 kg; horizontal components onlyΣFx = 12−8 = 4 N; ax = 4/2 = 2 m/s²
Original horizontal force model with proportional arrow lengths; not a complete vertical force inventory.

Because it is a vector equation, the second law also tells you the *direction* of the acceleration: an object always accelerates in the same direction as the net force acting on it. Rearranged, the same relationship lets you solve for whatever is unknown — acceleration a = ΣF ÷ m, or mass m = ΣF ÷ a. This one compact formula is the workhorse of the entire unit; nearly every problem you meet, from a sliding crate to an orbiting satellite, comes down to finding the net force and dividing by the mass.

Newton’s third law describes equal-magnitude opposite-direction interaction forces acting on two different bodies. They do not cancel in a free-body diagram of one body. A swimmer pushes water backward and receives a forward force from it. In walking, the foot can push the ground backward while static friction from the ground acts forward on the foot; vertical support is a separate component. Identify the receiving body for every arrow before summing forces.

Interaction partners belong on different free-body diagramsInteraction partners belong on different free-body diagramsbody Abody BB acts on A rightA acts on B leftEqual and opposite; different receiving bodies.
Original separated-body interaction diagram; arrow locations separate labels and are not a contact-geometry claim.

This third law explains how a rocket accelerates through the vacuum of space, where there is nothing outside to push against. The rocket hurls hot exhaust gas downward, and by the third law that gas pushes the rocket upward with equal force — the action-reaction pair is entirely between the rocket and its own exhaust. From walking to swimming to spaceflight, the three laws work as a team: the first tells you an object's motion only changes when forces are unbalanced, the second tells you exactly how much it changes, and the third reminds you that forces always come in pairs. Learn to read these three ideas together and you can predict the motion of almost anything.

Model check: Action/reaction forces act on different objects, so they do not cancel in one object’s diagram. a=Fnet/m=2 m/s² along the net force.

Build your understanding

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Part 1 · Use inertia without inventing a sustaining force

Inertia is the tendency to retain velocity when net force is zero in an inertial frame. An inertial frame is one where an unforced body moves at constant velocity. The displayed driving and resistance forces cancel horizontally; normal support and weight cancel vertically. This says acceleration is zero, not that the cart is necessarily at rest. Maintaining real steady motion often requires a drive to balance resistance, which differs from needing a forward net force.

Zero net force allows steady motionZero net force allows steady motionselected bodydrive 8 Ndrag 8 NnormalweightBalanced forces: a=0; velocity may be nonzero.
Original free-body diagram; equal opposing arrow lengths mark balance, not absence of interactions.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

Could this cart move at 3 m/s?

Visual reasoning — after your attempt

Yes. Balanced forces permit any constant velocity under this model.

In an inertial frame, zero net force means constant velocity, including the special case of rest. A moving object does not need a continuing forward net force to maintain ideal constant velocity. Real resistance often makes a driving interaction necessary to balance other forces.

A cart moving steadily can have several forces whose vector sum is zero. Zero net force is not the same as no interactions.

Pause and explain

Does constant velocity prove there are no forces?

Check your reasoning after answering

No. Forces can balance. It establishes zero acceleration in the model, not absence of all individual forces.

Part 2 · Apply the second law to the net force

For a constant-mass object in an inertial frame, Newton’s second law is ΣF=ma. Sigma means sum: use all external force components on that selected object. A 12 N pull opposed by 8 N produces 4 N net force, not 12 N. Dividing by 2 kg gives 2 m/s² along the net force. Vertical forces are omitted from this horizontal-only panel but must also be accounted for when the full motion requires them.

Acceleration uses the sum of forces on one bodyAcceleration uses the sum of forces on one bodyselected body12 N8 Nm = 2 kg; horizontal components onlyΣFx = 12−8 = 4 N; ax = 4/2 = 2 m/s²
Original horizontal force model with proportional arrow lengths; not a complete vertical force inventory.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

What acceleration results if both horizontal forces double?

Visual reasoning — after your attempt

The net becomes 24−16=8 N, giving 4 m/s² for unchanged 2 kg mass.

For constant mass in an inertial frame, ΣF=ma relates total external force to acceleration. Use all relevant forces on the chosen body, with consistent directions. A large single force can coexist with small acceleration if another force nearly balances it.

A 12 N pull and 8 N opposing resistance on a 2 kg cart give a 4 N net force and 2 m/s² acceleration.

Pause and explain

Which force belongs in ma?

Check your reasoning after answering

The vector sum of external forces on the chosen body, not merely the largest force or the force applied by one agent.

Part 3 · Place action-reaction forces on different bodies

Newton’s third law pairs the force B exerts on A with the force A exerts on B. Their magnitudes match and directions oppose, but they act on different bodies. They therefore do not cancel when calculating the acceleration of A alone. In a combined A+B system these mutual forces are internal and cancel in the total external-force account. Identify the agent and receiving body for every arrow before deciding which sum it belongs in.

Interaction partners belong on different free-body diagramsInteraction partners belong on different free-body diagramsbody Abody BB acts on A rightA acts on B leftEqual and opposite; different receiving bodies.
Original separated-body interaction diagram; arrow locations separate labels and are not a contact-geometry claim.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

Do equal interaction forces require equal accelerations of A and B?

Visual reasoning — after your attempt

No. Different masses can have different accelerations under equal-magnitude forces, and other forces may also act.

An interaction produces equal-magnitude opposite-direction forces on the two interacting bodies. They do not cancel in a free-body diagram of just one body because the partner force acts on the other. The resulting accelerations can differ because masses and other interactions differ.

A hand pushes a cart while the cart pushes the hand. The cart’s acceleration depends on forces on the cart, not a sum including the cart’s force on the hand.

Pause and explain

Why do third-law pairs not prevent acceleration?

Check your reasoning after answering

They act on different bodies. A net force calculation for one body includes only forces on that body.

Part 4 · Separate mass, weight, and measured support

Mass measures inertia in kilograms. Weight here means Earth’s gravitational force mg, while a scale reads a support interaction often called apparent weight. For a 50 kg person accelerating upward at 1.96 m/s², N=50(9.8+1.96)=588 N although mg remains 490 N. The normal force equals mg only when the vertical acceleration and other relevant vertical forces allow that balance. A scale reading change need not mean mass or local gravity changed.

Mass, gravitational weight and scale support are distinctMass, gravitational weight and scale support are distinctselected bodyN = 588 Nmg = 490 N50 kg passenger; elevator accelerates upward at 1.96 m/s²N−mg=ma; a scale measures support force.
Original elevator force account with schematic arrow scale; passenger remains in contact.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

What would the ideal scale read during downward acceleration of 1.96 m/s²?

Visual reasoning — after your attempt

N=50(9.8−1.96)=392 N; mass remains 50 kg.

Mass measures inertia in this model. Weight mg is the gravitational force near Earth; a scale commonly measures a support interaction. A scale reading can differ from mg during acceleration. Describe the actual measured force rather than using mass and weight interchangeably.

A scale in an upward-accelerating lift can report a support force greater than mg while the person’s mass stays unchanged.

Pause and explain

Does a larger lift scale reading mean mass increased?

Check your reasoning after answering

No. It reflects a changed support force needed for the acceleration; mass remains the same in this ordinary mechanical model.

Apply the whole unit · Explain an accelerating lift

Illustrative person of mass 60.0 kg accelerates upward at 2.0 m/s². Use g=10.0 m/s² and an ideal floor scale.

Your task

Draw forces on the person, find the scale reading, identify the floor-person third-law pair, and explain how the result differs from steady motion.

What your response should show

  • Define the system, quantities, units, and relevant conditions before selecting a model.
  • Show intermediate calculations or a labeled evidence account, including signs or denominators.
  • Explain how the supplied evidence supports the conclusion rather than reporting only an answer.
  • Identify a meaningful uncertainty, model limit, or measurement needed to test the conclusion.
Response guidance — after your attempt
  1. Weight=mg=600 N downward.

  2. N−600=60×2; support N=720 N upward.

  3. The person exerts 720 N downward on the floor; for steady velocity N would be 600 N.

The scale measures support, which exceeds weight during this upward acceleration. The floor’s support on the person and the person’s force on the floor are the third-law pair; support and gravity on the person are not that pair. A constant upward velocity would have zero acceleration and a different force balance.

Scientific references and source-model foundations

Parent / teacher teaching notes

Ask students to identify the receiver of every force. A correct numerical scale reading is insufficient if the proposed third-law pair acts on the same body. Ask the learner to explain each symbol, axis, unit and arrow before calculating. Calculated examples, supplied illustrative records and actual historical observations are labeled separately. Selected public OpenSciEd middle-school source figures are foundation examples, not complete high-school editions or an endorsement; all advanced explanations are supplied locally.

A free-body diagram showing force vectors acting on an object, illustrating how net force and mass set its acceleration under Newton's laws.

Force vectors acting on an object determine how it accelerates — combine them into a single net force, then apply ΣF = ma.

The key idea

First law: objects resist changes in motion (inertia). Second law: ΣF = ma. Third law: every force comes with an equal, opposite force on a different object.

Newton's Second Law

ΣF = ma

ΣF is the net force in newtons (N); m is mass in kg; a is acceleration in m/s². Rearranges to a = ΣF ÷ m or m = ΣF ÷ a.

The Newton

1 N = 1 kg·m/s²

one newton is the force that accelerates a 1 kg mass at 1 m/s².

Worked examples

Example 1

A net force of 84 N acts on a 12 kg cart on a frictionless surface. Find its acceleration.
  1. Rearrange ΣF = ma to solve for acceleration: a = ΣF ÷ m.
  2. a = 84 ÷ 12.
  3. = 7.
Answer: 7 m/s²

Example 2 · Worked application

A 4 kg cart has 18 N right and 6 N left acting horizontally. Find acceleration.
  1. Net force=18−6=12 N right.
  2. a=F_net/m=12/4=3 m/s² right.
  3. Sum forces on the cart only.
Answer: 3 m/s² right.
Check the reasoning

The reaction to a push acts on the other object, not automatically in this force sum.

Example 3

A 1,500 kg car accelerates at 4 m/s². What net force must act on it?
  1. Use ΣF = ma.
  2. ΣF = 1,500 × 4.
  3. = 6,000.
Answer: 6,000 N

Example 4 · Find and fix the mistake

Context: A 4 kg cart has 18 N right and 6 N left acting horizontally. Find acceleration. A student claims: “Motion requires a continuing net force in the direction of velocity.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: The reaction to a push acts on the other object, not automatically in this force sum.
  2. A nonzero net force changes velocity; constant velocity is consistent with zero net force.
Answer: A nonzero net force changes velocity; constant velocity is consistent with zero net force.
Check the reasoning

The reaction to a push acts on the other object, not automatically in this force sum.

Example 5 · Reason from the visual model

Interaction partners belong on different free-body diagramsInteraction partners belong on different free-body diagramsbody Abody BB acts on A rightA acts on B leftEqual and opposite; different receiving bodies.
Original separated-body interaction diagram; arrow locations separate labels and are not a contact-geometry claim.
Do equal interaction forces require equal accelerations of A and B?
  1. Newton’s third law pairs the force B exerts on A with the force A exerts on B. Their magnitudes match and directions oppose, but they act on different bodies. They therefore do not cancel when calculating the acceleration of A alone. In a combined A+B system these mutual forces are internal and cancel in the total external-force account. Identify the agent and receiving body for every arrow before deciding which sum it belongs in.
  2. No. Different masses can have different accelerations under equal-magnitude forces, and other forces may also act.
Answer: No. Different masses can have different accelerations under equal-magnitude forces, and other forces may also act.
Check the reasoning

Original separated-body interaction diagram; arrow locations separate labels and are not a contact-geometry claim.

Avoid these mistakes

Check your understanding

A 3 kg cart has 6N net force. Find acceleration.

Discuss the answer

a=Fnet/m=2 m/s² along the net force.

Return to the phenomenon

Return to the initial case. Why can a moving cart have zero net force? Revise your drawing or explanation using two named ideas and one stated limitation.

Compare explanations after your attempt

Balanced forces give zero acceleration, not necessarily zero velocity; interaction partners belong to different objects.

What should we investigate next?

Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.

Investigate, calculate and revise

Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.

Activity 1 · Return to the opening case

Assigned reading and preparation

Use the opening phenomenon, unit definitions and explained Parts 1–4.

Your task

Return to the initial case. Why can a moving cart have zero net force? Revise your drawing or explanation using two named ideas and one stated limitation.

Success criteria

  • Use the stated observations and appropriate units.
  • Connect a labeled model with the physical/environmental mechanism.
  • State assumptions and an evidence limitation.
  • Explain a substantive revision or next test.
Hint

Keep object/material identity, material transfer and energy account distinct.

Response guidance — discuss after your attempt

Balanced forces give zero acceleration, not necessarily zero velocity; interaction partners belong to different objects.

Activity 2 · Transfer to a changed case

Assigned reading and preparation

Cover the worked answer and use the explained models, relationships and notebook.

Your task

A 4 kg cart has forces 18 N east and 6 N west. Find acceleration and the partner of the 18 N force.

Success criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the physical or environmental mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.
Hint

Name known quantities and conditions, show intermediate steps and check conservation.

Response guidance — discuss after your attempt

Net=12 N east; a=3 m/s² east. Its third-law partner is the cart’s 18 N force on the pulling agent, not the 6 N resistance on the cart.

Words to know

inertia
The tendency of an object to resist any change in its state of motion; measured by its mass.
Newton's first law
An object at rest stays at rest, and an object in motion stays in motion at constant velocity, unless acted on by a nonzero net force.
Newton's second law
The net force on an object equals its mass times its acceleration: ΣF = ma.
Newton's third law
For every force one object exerts on a second, the second exerts an equal and opposite force back on the first.
newton (N)
The SI unit of force; 1 N is the force that accelerates 1 kg at 1 m/s², so 1 N = 1 kg·m/s².

From Aristotle to the Principia: a 2,000-year correction

For nearly two millennia, the ancient Greek philosopher Aristotle taught that objects have a 'natural' state of rest and that a continuous force is required to keep anything moving — an idea that matches everyday experience, since carts stop when you stop pushing. Galileo Galilei challenged this in the early 1600 s by imagining perfectly smooth surfaces, reasoning that a ball would roll forever if friction could be removed. In 1687 Isaac Newton published his Principia Mathematica, one of the most influential books in the history of science, which gathered these insights into three crisp laws. The first law's radical claim — that constant velocity, not rest, is the natural state when no net force acts — overturned common sense and launched modern physics.

Does motion require a force? The stubborn misconception

The single most common error in introductory physics is believing that a moving object must have a force pushing it in its direction of travel. It feels obvious: stop pedaling and your bike coasts to a halt. But the bike slows because of friction and air resistance pushing backward, not because it 'ran out of force.' A hockey puck on near-frictionless ice glides at nearly constant speed with no forward force at all. Whenever you see something moving steadily in a straight line, the correct conclusion is that the net force on it is zero — the forces are balanced, exactly as they are for an object sitting still.

Momentum and impulse: the deeper form of the second law

Newton originally framed his second law in terms of momentum, p = mv — a kind of 'quantity of motion.' In this form, force is the rate at which momentum changes: F = Δp/Δt, which rearranges to the impulse relationship F·Δt = Δp. This explains why airbags and crumple zones save lives: they stretch out the time Δt over which a crash brings you to a stop, so the same change in momentum happens with a much smaller force on your body. The familiar ΣF = ma is just this deeper law written for the common case where mass stays constant, which is why momentum ideas underlie collisions, rockets, and recoil.

Rockets in a vacuum: the third law at full throttle

A persistent myth says rockets work by 'pushing against the air,' which would make spaceflight impossible. In truth, a rocket obeys Newton's third law: it throws exhaust gas out the back at high speed, and the gas pushes the rocket forward with an equal and opposite force. The Saturn V that carried astronauts to the Moon weighed roughly 2.9 million kilograms fully fueled and produced about 34 million newtons of thrust at liftoff — enough to overcome its enormous weight. Because the action–reaction pair is entirely between the rocket and its own expelled gas, a rocket accelerates just as well in the vacuum of space as in the atmosphere.

In the real world

Every rocket launch is Newton's third law at full power: engines fling exhaust gas downward, and the gas pushes the rocket up — which is why rockets work even in the vacuum of space.

Exit check

A3 kg cart has 6N net force. Find acceleration.

Check your explanation after answering

a=Fnet/m=2 m/s² along the net force.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Problem 1

A net force of 36 N acts on a 4 kg block on a frictionless surface. Find its acceleration.
Answer and explanation

9 m/s²

a = ΣF ÷ m = 36 ÷ 4 = 9 m/s².

Problem 2

A club strikes a 0.045 kg golf ball, giving it an acceleration of 2,000 m/s². What net force did the club apply?
Answer and explanation

90 N

ΣF = ma = 0.045 × 2,000 = 90 N.

Problem 3

A book rests on a table. Earth pulls the book down with the force of gravity. According to Newton's third law, what is the reaction force to this pull?
  1. The book pulling up on the Earth
  2. The book's inertia
  3. The table pushing up on the book
  4. The book pushing down on the table
Answer and explanation

The book pulling up on the Earth

A third-law pair acts on two different objects. If Earth pulls the book down, the reaction is the book pulling Earth up. (The table's push is a separate force, not the reaction to gravity.)

Problem 4

A 1,000 kg elevator rises at a constant velocity. What is the net force on it?
  1. Greater than its weight
  2. Zero
  3. 9,800 N upward
  4. 1,000 N upward
Answer and explanation

Zero

Constant velocity means zero acceleration, so by ΣF = ma the net force must be zero — the cable tension exactly balances the weight.

Problem 5

Explain, using Newton's first law, why a passenger's head snaps backward when a car is rear-ended and lurches forward.
Answer and explanation

Before the impact the passenger's head is at rest. When the car and seat are suddenly pushed forward, the head tends to stay where it was because of inertia (Newton's first law), so it lags behind the moving body and appears to snap backward. A headrest supplies the force needed to accelerate the head along with the body, preventing whiplash.

Problem 6

Two horizontal forces act on a 5 kg object on frictionless ice: 40 N east and 15 N west. Find the object's acceleration.
Answer and explanation

5 m/s²

Net force = 40 − 15 = 25 N east. a = ΣF ÷ m = 25 ÷ 5 = 5 m/s² east.

Problem 7

A 3 kg object accelerates at 2 m/s². Find net force. Show the reasoning, not just the conclusion.
Hints

The reaction to a push acts on the other object, not automatically in this force sum.

Answer and explanation

F_net=ma=6 N in the acceleration direction.

Problem 8

How can a small car and heavy truck exert equal collision forces but have different accelerations?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

Their interaction forces are equal and opposite; acceleration magnitude depends on each mass.

Problem 9

Interaction partners belong on different free-body diagramsInteraction partners belong on different free-body diagramsbody Abody BB acts on A rightA acts on B leftEqual and opposite; different receiving bodies.
Original separated-body interaction diagram; arrow locations separate labels and are not a contact-geometry claim.
Interpret the supplied visual. Do equal interaction forces require equal accelerations of A and B?
Answer and explanation

No. Different masses can have different accelerations under equal-magnitude forces, and other forces may also act.

Newton’s third law pairs the force B exerts on A with the force A exerts on B. Their magnitudes match and directions oppose, but they act on different bodies. They therefore do not cancel when calculating the acceleration of A alone. In a combined A+B system these mutual forces are internal and cancel in the total external-force account. Identify the agent and receiving body for every arrow before deciding which sum it belongs in.

No. Different masses can have different accelerations under equal-magnitude forces, and other forces may also act.

Response criteria

  • Interpret labels, structures, axes, units and directions correctly.
  • Explain the physical or environmental relationship or mechanism.
  • Respect stated assumptions and distinguish observation from inference.

Problem 10

A 4 kg cart has forces 18 N east and 6 N west. Find acceleration and the partner of the 18 N force.
Answer and explanation

Net=12 N east; a=3 m/s² east. Its third-law partner is the cart’s 18 N force on the pulling agent, not the 6 N resistance on the cart.

Net=12 N east; a=3 m/s² east.

Its third-law partner is the cart’s 18 N force on the pulling agent, not the 6 N resistance on the cart.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the physical or environmental mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

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