Describing Motion — Print · Grade 12 Science
Chapter: Motion & KinematicsDescribing Motion
Learning goals
- I can describe an object's position relative to a chosen origin and reference frame.
- I can distinguish distance from displacement, and scalars from vectors, and calculate a resultant displacement.
- I can explain how the same motion looks different from different frames of reference.
Readings for this unit
Before this unit
Axes, signs, scalar/vector distinction.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
How can a moving object finish with zero average velocity?
Illustrative evidence case. A traveler leaves a doorway and returns to it after four seconds.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
How can a moving object finish with zero average velocity?
Your first model
Keep both the route and a position–time record.
Build the language from the idea
- position
- An object's location relative to a chosen reference point (the origin), usually given as a coordinate with a sign for direction.
- distance
- The total length of the path an object travels; a scalar, always positive, with no direction.
- displacement
- The straight-line change in position from start to finish, with direction: Δx = x_final − x_initial. A vector.
- scalar
- A quantity with magnitude only, such as distance, speed, time, or mass.
- vector
- A quantity with both magnitude and direction, such as displacement, velocity, or acceleration.
- frame of reference
- The point of view — a chosen origin and coordinate system — from which position and motion are measured.
Before you can say how something moves, you have to agree on where it is, and that always starts with a choice. You pick an origin — a reference point you're calling zero — and then an object's position is just its location measured from that origin, complete with a sign that tells you which side it's on. A hiker 5 km east of the trailhead is at position +5 km; a diver 5 km west is at −5 km. Physics doesn't hand you the origin; you choose it to make the problem simple, and every number that follows is measured against it.
Once positions are pinned down, two very different questions about a trip come apart. Distance is the total path length actually traveled — every step, every detour, added up — and it never carries a direction or a sign. Displacement is the straight-line change in position from start to finish, written Δx = x_final − x_initial, and it does carry direction. Walk 40 m east and then 30 m west and you've covered a distance of 70 m, but your displacement is only 10 m east. Run one full lap of a track and return to the start, and you've logged hundreds of meters of distance for a displacement of exactly zero.
That contrast is really the difference between two families of quantities. A scalar has size only — distance, speed, time, temperature, and mass are all scalars, fully described by a number and a unit. A vector has both size and direction — displacement, velocity, and acceleration are vectors, and leaving out the direction throws away half the information. This is why physicists are so fussy about arrows and signs: '10 m' answers a different question than '10 m east,' and in two dimensions the direction can be the whole point.
Vectors also combine differently than plain numbers, because directions can partly cancel or reinforce. When two displacements lie along the same line you simply add or subtract them, but when they meet at a right angle you combine them with the Pythagorean theorem. A drone that flies 40 m east and then 30 m north hasn't ended up 70 m from home — it's √(40² + 30²) = √2500 = 50 m away, along a diagonal. The path length (distance) and the straight-line result (displacement magnitude) genuinely differ, and only careful vector arithmetic gets the second one right.
Every one of these measurements secretly depends on a frame of reference — the origin and coordinate system you're measuring from. Sit still reading on a moving train and, in the train's frame, your velocity is zero; in the platform's frame you're rushing past at 100 km/h; in the Sun's frame you're hurtling through space at tens of kilometers per second. None of these is 'the real' answer, because there is no absolute, universal resting point in the universe. Motion is always relative to a chosen frame, and two observers in different frames can honestly disagree about how fast — or even whether — something is moving.
Getting fluent with these ideas is what makes the rest of kinematics possible. Position gives you the 'where,' displacement and distance separate the net change from the total journey, the scalar–vector split keeps direction in the accounting, and the frame of reference reminds you to state whose point of view you're using. Air-traffic controllers, GPS receivers, and self-driving cars all run on exactly this framework — tracking positions as coordinates and displacements as vectors, always relative to a clearly defined reference frame.
Model check: Distance traveled and displacement can differ even on a straight line. Distance 8 m; displacement+2 m with east positive.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Choose a frame, origin, and positive direction
Position locates an object relative to a selected origin at a particular time. Displacement subtracts initial position from final position in that same frame. Moving from −1 m to +2 m gives +3 m, not +1 m. A positive coordinate does not by itself tell whether the object is moving right, and the origin is not necessarily the release point. Preserve event times and the chosen sign convention in your notebook.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
If the origin moves 5 m right, what are the new positions and displacement?
Visual reasoning — after your attempt
The positions become −6 m and −3 m; their difference remains +3 m.
Position describes location relative to a selected origin and reference frame. Coordinates are labels for locations; they do not measure the length of the route already traveled. Two observers can assign different coordinates while agreeing on a carefully defined physical event.
State whether east, right, or upward is positive. Shifting the origin changes positions but not the displacement between the same two events.
Pause and explain
Does changing the origin change the displacement?
Check your reasoning after answering
No. Subtracting final and initial coordinates cancels a constant origin shift, provided the frame and axis directions are otherwise the same.
Part 2 · Distinguish path distance from displacement
Distance traveled adds nonnegative lengths of all parts of a path. Displacement compares only the endpoints. A walker goes 5 m east and then 3 m west: distance is 8 m, but east-positive displacement is +2 m. Returning to the starting point gives zero displacement without zero distance. Neither quantity specifies the entire timing history, so a path sketch should be paired with a clock record when the question asks about speed or velocity.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
What would the distance and displacement be after 5 m east and 5 m west?
Visual reasoning — after your attempt
Distance=10 m; displacement=0 m in this frame.
Distance accumulates the length of the route and is nonnegative. Displacement is final position minus initial position and can include direction. A return trip can have substantial distance and zero net displacement. Identify which quantity a question asks before dividing by time.
Walking 30 m east and 10 m west gives distance 40 m but displacement 20 m east. A sketch makes the difference visible.
Pause and explain
Can distance be smaller than displacement magnitude?
Check your reasoning after answering
For a physical route between the same endpoints, distance is at least the displacement magnitude; a straight direct route can make them equal.
Part 3 · Distinguish average speed from average velocity
An average rate divides a defined change or amount by elapsed time. Average speed is total distance divided by duration; average velocity is displacement divided by duration. The same 4-second journey can therefore have 2 m/s average speed but only +0.5 m/s average velocity. Averaging two segment speeds by ordinary arithmetic works only for equal segment times. For unequal times, use total distance and total duration or the appropriate time-weighted calculation.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Can you infer the maximum instantaneous speed from this table?
Visual reasoning — after your attempt
No. It supplies totals and duration, not the full motion history between events.
Average speed is total distance divided by elapsed time. Average velocity uses net displacement over that same interval. Neither average reveals all moment-by-moment behavior, and a zero average velocity does not imply rest throughout. Use the full interval, including stops when they belong to it.
A round trip returning to its start has zero average velocity, but positive average speed if it covers distance in nonzero time.
Pause and explain
What extra information is needed for instantaneous motion?
Check your reasoning after answering
A sufficiently detailed time record or a justified motion model is needed; one whole-trip average does not identify velocity at every instant.
Part 4 · Test a motion claim with an explicit record
A motion record links positions with clock readings in a named frame. Here position first increases, then decreases, and returns to the origin. If each connecting segment represents constant velocity, the model gives +2 m/s followed by −2 m/s. The sampled positions alone do not resolve the exact shape of the turnaround or any brief acceleration between samples. Separate a displayed observation from an interpolation assumption before judging claims such as “the object never moved.”
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Find modeled total distance and average velocity over 4 s.
Visual reasoning — after your attempt
Distance=4+4=8 m; displacement=0 and average velocity=0 m/s.
A useful motion record supplies times, locations, directions, and any assumptions between measurements. Sparse positions can support interval averages but not an exact detailed route. Compare interpretations against the whole record rather than selecting one convenient coordinate.
A flat position interval can indicate rest in that frame, but equal starting and ending positions alone could also hide a trip out and back.
Pause and explain
Do equal endpoint positions establish that the object never moved?
Check your reasoning after answering
No. They establish zero displacement. Intermediate positions or other evidence are required to distinguish continuous rest from an excursion.
Apply the whole unit · Explain an out-and-back record
Illustrative trip: start x=0 m; move to x=+30 m in 10 s; return to x=+10 m in the next 10 s. Assume straight segments along one axis.
Your task
Find path distance, net displacement, average speed, and average velocity. Explain what the endpoint record alone cannot establish.
What your response should show
- Define the system, quantities, units, and relevant conditions before selecting a model.
- Show intermediate calculations or a labeled evidence account, including signs or denominators.
- Explain how the supplied evidence supports the conclusion rather than reporting only an answer.
- Identify a meaningful uncertainty, model limit, or measurement needed to test the conclusion.
Response guidance — after your attempt
Distance=30+20=50 m; displacement=+10−0=+10 m.
Total time=20 s; average speed=50/20=2.5 m/s.
Average velocity=10/20=+0.50 m/s.
The different averages answer different questions: travel accumulated along the route versus net change in position. These values do not imply constant speed on each segment unless an additional model is supplied. A person seeing only the start and finish would know displacement but could not recover the 50 m route.
Scientific references and source-model foundations
Parent / teacher teaching notes
Require students to write a sentence identifying the interval and frame for every average, then test their definitions with a complete return to the origin. Ask the learner to explain each symbol, axis, unit and arrow before calculating. Calculated examples, supplied illustrative records and actual historical observations are labeled separately. Selected public OpenSciEd middle-school source figures are foundation examples, not complete high-school editions or an endorsement; all advanced explanations are supplied locally.
The key idea
Position is measured from a chosen origin; distance is total path length (a scalar) while displacement is the straight-line change in position (a vector), and every measurement is made relative to a frame of reference.
Displacement
Δx = x_final − x_initial
x_final and x_initial are positions along a chosen axis (each with a sign); Δx is a vector, and its sign gives the direction. Distance, in contrast, is the total path length and is always positive.
Resultant of perpendicular displacements
d = √(Δx² + Δy²)
when two displacement legs meet at a right angle (e.g. east then north), combine them with the Pythagorean theorem; d is the straight-line displacement magnitude.
Worked examples
Example 1
- Distance is the total path length: 40 + 30 = 70 m.
- The two legs meet at a right angle, so combine them with the Pythagorean theorem: displacement = √(40² + 30²).
- = √(1600 + 900) = √2500 = 50.
Example 2 · Worked application
- Distance sums path lengths: 50+20=70 m.
- Choose east positive: displacement=50−20=30 m.
- Distance is scalar; displacement includes direction.
Final minus initial position should match the signed path sum.
Example 3
- Use Δx = x_final − x_initial.
- Δx = (−2) − (+8) = −10.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: Final minus initial position should match the signed path sum.
- They agree in magnitude only for some paths; changes of direction distinguish them.
Final minus initial position should match the signed path sum.
Example 5 · Reason from the visual model
- An average rate divides a defined change or amount by elapsed time. Average speed is total distance divided by duration; average velocity is displacement divided by duration. The same 4-second journey can therefore have 2 m/s average speed but only +0.5 m/s average velocity. Averaging two segment speeds by ordinary arithmetic works only for equal segment times. For unequal times, use total distance and total duration or the appropriate time-weighted calculation.
- No. It supplies totals and duration, not the full motion history between events.
Illustrative aggregate record; no uniform speed between endpoints is assumed.
Avoid these mistakes
- Distance traveled and displacement can differ even on a straight line.
Check your understanding
Walk 5 m east then 3 m west. Give distance and displacement.
Discuss the answer
Distance 8 m; displacement+2 m with east positive.
Return to the phenomenon
Return to the initial case. How can a moving object finish with zero average velocity? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Zero endpoint displacement gives zero average velocity, while traveled distance and average speed can be positive.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. How can a moving object finish with zero average velocity? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the physical/environmental mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep object/material identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Zero endpoint displacement gives zero average velocity, while traveled distance and average speed can be positive.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
A student walks 12 m north in 6 s, then 4 m south in 4 s. Find average speed and average velocity, taking north positive.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
Distance=16 m and elapsed time=10 s, so average speed=1.6 m/s. Displacement=+8 m, so average velocity=+0.8 m/s. Do not average the segment speeds without time weighting.
Words to know
- position
- An object's location relative to a chosen reference point (the origin), usually given as a coordinate with a sign for direction.
- distance
- The total length of the path an object travels; a scalar, always positive, with no direction.
- displacement
- The straight-line change in position from start to finish, with direction: Δx = x_final − x_initial. A vector.
- scalar
- A quantity with magnitude only, such as distance, speed, time, or mass.
- vector
- A quantity with both magnitude and direction, such as displacement, velocity, or acceleration.
- frame of reference
- The point of view — a chosen origin and coordinate system — from which position and motion are measured.
There is no such thing as absolute rest
It feels obvious that the ground beneath you is 'not moving,' but physics insists otherwise. Right now you are spinning with Earth's surface at hundreds of meters per second, orbiting the Sun at about 30 km/s, and drifting with the whole solar system through the galaxy faster still. Which of these is your 'true' speed? The answer is that there isn't one. Galileo's principle of relativity says the laws of motion are the same in every uniformly moving frame, so no experiment can single out an absolute resting point. This is why you can pour a drink on a smoothly cruising airplane exactly as you would at home — inside that frame, everything behaves as if you were at rest. Motion is only ever defined relative to a chosen frame of reference.
Why displacement can be smaller than distance — and never larger
Distance is the length of the actual path; displacement is the straight-line shortcut from start to finish. Since the straight line between two points is the shortest route, displacement can never exceed distance, and the two are equal only when the motion is a straight line that never reverses. The gap between them is a measure of how much the path wandered or doubled back: a 400 m lap has 400 m of distance but zero displacement, while a diagonal walk of 40 m east and 30 m north covers 70 m of path for just 50 m of displacement. Whenever a problem gives you a winding route, that gap is the first clue that distance and displacement will disagree.
Vectors: adding tip-to-tail and breaking into components
Vectors don't add like ordinary numbers because directions can reinforce or cancel. To add them graphically you place them tip-to-tail — the start of the second at the end of the first — and draw a single arrow from the very beginning to the very end; that arrow is the resultant. The reverse trick is even more powerful: any vector can be broken into perpendicular components, usually one horizontal and one vertical, using v_x = v·cosθ and v_y = v·sinθ. This 'resolve into components' move is the workhorse of the entire unit — it's exactly how a diagonal displacement becomes a clean right triangle, and how an angled launch becomes two independent motions in the projectile lesson.
From Descartes' grid to GPS coordinates
The idea of pinning a position to numbers on axes comes from René Descartes in the 1600 s, whose coordinate grid let geometry be written as algebra — which is why we still call them Cartesian coordinates. That same idea now runs the modern world: a GPS receiver finds your position by timing signals from at least four satellites, each broadcasting where it is and when, and solving for the one point in three-dimensional coordinates consistent with all of them. The receiver reports latitude, longitude, and altitude — a position vector relative to Earth's center — and tracks how that vector changes to compute your displacement and velocity. Every 'you are here' dot is a physics coordinate problem solved dozens of times a second.
In the real world
A GPS receiver reports your position as coordinates relative to Earth's center and computes your displacement as a vector, which is how a navigation app knows both how far you are from your destination and in which direction to send you.
Exit check
Walk 5 m east then 3 m west. Give distance and displacement.
Check your explanation after answering
Distance 8 m; displacement+2 m with east positive.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Problem 1
Answer and explanation
13 km
Distance is total path length: 8 + 5 = 13 km.
Problem 2
Answer and explanation
3 km
Displacement combines opposite directions: 8 − 5 = 3 km east.
Problem 3
- displacement
- speed
- distance
- mass
Answer and explanation
displacement
Displacement has both magnitude and direction, making it a vector. Distance, speed, and mass are scalars.
Problem 4
- Its distance and displacement are both zero
- Its distance is zero but its displacement is large
- Its displacement is zero but its distance equals the track's length
- Its displacement equals the track's length
Answer and explanation
Its displacement is zero but its distance equals the track's length
Returning to the start makes the displacement zero, while the distance traveled equals the full length of the lap.
Problem 5
Answer and explanation
13 m
The legs are perpendicular, so displacement = √(12² + 5²) = √169 = 13 m.
Problem 6
Answer and explanation
Velocity is always measured relative to a frame of reference. In the train's frame, the seated passenger isn't moving, so her velocity is zero. In the platform's frame, she is carried along with the train at, say, 100 km/h. Both are correct within their own frame because there is no absolute resting point in the universe — motion is relative to whatever origin you measure from.
Problem 7
Hints
Final minus initial position should match the signed path sum.
Answer and explanation
Distance 400 m; displacement 0 m.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Coordinates depend on the chosen reference frame; changes can then be interpreted consistently.
Problem 9
Answer and explanation
No. It supplies totals and duration, not the full motion history between events.
An average rate divides a defined change or amount by elapsed time. Average speed is total distance divided by duration; average velocity is displacement divided by duration. The same 4-second journey can therefore have 2 m/s average speed but only +0.5 m/s average velocity. Averaging two segment speeds by ordinary arithmetic works only for equal segment times. For unequal times, use total distance and total duration or the appropriate time-weighted calculation.
No. It supplies totals and duration, not the full motion history between events.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
Distance=16 m and elapsed time=10 s, so average speed=1.6 m/s. Displacement=+8 m, so average velocity=+0.8 m/s. Do not average the segment speeds without time weighting.
Distance=16 m and elapsed time=10 s, so average speed=1.6 m/s.
Displacement=+8 m, so average velocity=+0.8 m/s.
Do not average the segment speeds without time weighting.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.