Superposition, Standing Waves & Resonance — Practice · Grade 12 Science
Chapter: Waves, Sound & OpticsWhat this practice covers
By the end of Superposition, Standing Waves & Resonance you should be able to:
- I can combine wave displacements and identify nodes and antinodes.
- I can calculate fixed-string harmonics and explain resonance limits.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: node, antinode, resonance.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
0.6 m
Node spacing=λ/2.
Problem 2
Answer and explanation
No; it describes local combined displacement. The waves can continue and energy distribution must be considered.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
60 Hz
4×15=60.
Problem 4
Answer and explanation
Fixed, free, open, and closed boundaries allow different mode patterns.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
Boundary conditions determine allowed wavelengths.
Answer and explanation
f₂=2f₁=20 Hz.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Their displacements cancel locally by superposition; this does not imply energy is destroyed everywhere.
Problem 7
Answer and explanation
L=2λ/2, so λ=1.2 m.
A standing wave has nodes of zero displacement amplitude and antinodes of maximum amplitude, produced by counterpropagating coherent waves under appropriate conditions. A string fixed at both ends has nodes there and supports L=nλ/2. The displayed second harmonic has an additional middle node. Air columns with an open end have different displacement/pressure boundary conditions; do not transfer the fixed-string formula without identifying what is constrained.
L=2λ/2, so λ=1.2 m.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
f1=v/(2L)=10 Hz; f3=30 Hz. λ3=2L/3=1.0 m, with fixed-end nodes in this ideal string model.
f1=v/(2L)=10 Hz; f3=30 Hz. λ3=2L/3=1.0 m, with fixed-end nodes in this ideal string model.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.