Calculus I · The Function That Is Its Own Slope

Hunting for the base that leaves the axis at slope 1

We want the base aa where the curve crosses the yy-axis at slope exactly 11 — where M(a)=1M(a) = 1. Let us just measure M(a)M(a) for a few bases by taking very small hh in ah−1h\dfrac{a^h - 1}{h}. (This is the kind of thing a calculator, or the notebook for this chapter, does in a heartbeat. Try h=0.0001h = 0.0001.)

base aa slope at the axis, M(a)M(a)
22 ≈0.693\approx 0.693
2.52.5 ≈0.916\approx 0.916
2.7182.718 ≈1.000\approx 1.000
33 ≈1.099\approx 1.099
1010 ≈2.303\approx 2.303

For a=2a = 2 the curve leaves the axis too gently — slope only 0.6930.693. For a=3a = 3 it leaves a little too steeply — slope 1.0991.099. So somewhere between 22 and 33 there is a base where the slope is exactly 11. (If you want this argument made airtight: M(a)M(a) slides smoothly upward as aa grows, it is below 11 at a=2a=2 and above 11 at a=3a=3, so it must hit 11 somewhere in between. We will sharpen “slides smoothly” later, but the picture is honest.)

That special base gets its own letter. We call it ee:

e≈2.71828…e \approx 2.71828\ldots

and it is defined to be the base for which M(e)=1M(e) = 1. The instant we say that, the boxed rule gives us our prize:

ddxex=M(e)⋅ex=1⋅ex=ex.\frac{d}{dx}e^{x} = M(e)\cdot e^{x} = 1\cdot e^{x} = e^{x}.

ddxex=ex\boxed{\;\frac{d}{dx}\,e^{x} = e^{x}\;}

This is the function that is its own slope. We did not pull it out of a hat. We went looking for a function equal to its own derivative, discovered that every exponential is almost one (off only by a constant M(a)M(a)), and then picked the one base that makes the constant vanish. The number ee is exactly the price of that wish.

(Figure 5.2: y=exy = e^x with tangent lines drawn at several points. At every point, the steepness of the tangent equals the height of the curve. Where the curve is at height 55, the slope is 55. That is what “its own derivative” looks like.)

Figure 5.2
Figure 5.2

A promise about ee, to be kept in Chapter 1’s other form

Back in Chapter 1, when we played with sequences, we watched the quantity (1+1n)n\left(1 + \frac{1}{n}\right)^n creep upward as nn grew — 22, then 2.252.25, then 2.4883…2.4883\ldots, settling toward 2.718…2.718\ldots. That was the same number ee. It is not obvious that “the base whose curve leaves the axis at slope 11” and “the number that (1+1n)n\left(1+\frac1n\right)^n sneaks up on” are the same number. They are. This is the loan I warned you about. For now, take it as a promise backed by the matching decimals; in Chapter 10, with integrals in hand, we will prove the two descriptions of ee are genuinely one number.

Figure 5.3
Figure 5.3

Toolkit: Differentiating exponentials

  • ddxex=ex\displaystyle \frac{d}{dx}\,e^{x} = e^{x} — the headline. The function is its own derivative.
  • ddxekx=kekx\displaystyle \frac{d}{dx}\,e^{kx} = k\,e^{kx} — by the chain rule from Chapter 4 (outer function e(⋅)e^{(\cdot)}, inner function kxkx, inner derivative kk).
  • ddxax=(ln⁡a)ax\displaystyle \frac{d}{dx}\,a^{x} = (\ln a)\,a^{x} — the mystery constant M(a)M(a) turns out to be ln⁡a\ln a. We prove this two pages from now.

The middle line is the one you will use most. The constant kk being positive means growth; kk negative means decay. That single sign is the difference between rabbits and radioactivity.


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