Gravity & Friction — Print · Grade 8 Science

Gravity & Friction

Learning goals

I can describe how gravity depends on mass, and calculate weight using W = mg.
I can describe how friction opposes motion and identify factors that change its strength.
I can argue from mass/distance evidence and distinguish free fall from significant drag.

Readings for this unit

A moving cart and a magnet across a gap

Before this unit

Distinguish mass from gravitational force.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in gravity & friction?

Illustrative evidence case. An illustrative 2 kg object has weight 19.6 N using Earth g=9.8 N/kg and 3.2 N using a modeled Moon g=1.6 N/kg. Both trials use the same object. A released ball can still be rising while its acceleration points downward. The trajectory drawing shows the same downward acceleration on the way up, at the top, and on the way down. Use it to distinguish the direction of motion from the direction of change in motion.

The ball starts with horizontal velocity 6 m/s and upward velocity 10 m/s. In this ideal near-Earth model, no air drag acts and g is rounded to 10 m/s². Equal-time dots are equally spaced horizontally, while height first rises and then falls. Blue velocity arrows are tangent to the path; red acceleration arrows remain downward at the top as well as elsewhere. Vertical velocity is zero at 1 s, but horizontal velocity is not. After release the hand no longer pushes the ball. The gray curve is a physical path, not a time graph; velocity and acceleration arrow lengths use separate scales.

Notice and wonder

Why does the object retain its mass on the Moon? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Explain the mass and weight comparison, then identify a friction test that would isolate surface type. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

gravity: An attractive force between any two objects with mass; bigger masses and closer distances create a stronger pull.
weight: The force of gravity on an object's mass, calculated as weight = mass × g (W = mg).
mass: The amount of matter in an object, measured in kilograms; it doesn't change no matter where the object is.
friction: A force that opposes motion between two surfaces in contact.
air resistance: A type of friction caused by air pushing against a moving object.
model: A representation that explains selected features and makes predictions; it leaves other details out.
evidence: Relevant observations or records used to support or challenge a claim.
system boundary: The chosen limit separating the objects being studied from their surroundings.
assumption: A condition taken as true for a model or calculation and needing to be checked against the case.

Gravity is an attractive interaction between objects with mass. Its strength depends on the masses and separation. Near Earth, the ideal free-fall acceleration is approximately 9.8 m/s² when air resistance is negligible. A heavier object has greater weight but also greater inertia, giving the same ideal acceleration. Different shapes can fall differently in air because drag affects their motion. State the model assumptions rather than claiming that every real falling object has identical acceleration.

That pull gives every object a weight, calculated as weight = mass × g, or W = mg, and measured in newtons (N) like any other force. It's tempting to treat weight and mass as the same thing, but they're genuinely different. Mass is the amount of matter packed into an object (measured in kilograms), and it never changes no matter where the object goes. Weight is the force of gravity acting on that mass, so it changes whenever gravity changes.

The Moon makes the difference vivid. An astronaut has the exact same mass on the Moon as on Earth — she's made of the same amount of matter either way. But the Moon is much smaller, so its gravity is only about a sixth as strong, and she therefore weighs only about a sixth as much. She could bound across the surface in giant leaps not because she lost any mass, but because the force pulling her down got weaker.

Friction resists relative sliding, or the tendency to slide, between contacting surfaces. It can depend on surface materials, microscopic contact interactions, normal force, and whether surfaces are already sliding. Surface roughness alone is not a universal predictor. Friction may oppose a sliding box’s motion, but static friction can provide the forward force that helps a person walk. Describe the contact and relative motion before assigning a friction arrow.

For a box sliding right relative to a stationary floor, friction on the box points left. During ordinary forward walking, a planted shoe pushes backward on the ground; static friction from the ground can push the shoe and walker forward while the contact does not slide. The red arrows belong to the named receiver. The force on the ground is the opposite interaction partner on another object. Vertical weight and support forces are omitted in this horizontal comparison.

Air resistance is a specific kind of friction — the push of air against anything moving through it. It's the reason a feather drifts slowly to the floor while a rock plummets, even though gravity pulls on both. The feather's large surface area and tiny mass let air resistance hold it back far more, relative to its weight. This leads to a famous surprise: in a vacuum with no air at all, a feather and a rock dropped together actually hit the ground at the exact same instant — a result astronauts have demonstrated on the airless Moon.

Friction depends on contact materials, surface conditions and the forces pressing surfaces together. It can slow sliding, but it also lets shoes grip the ground and tires push a road. Static friction can act without visible sliding.

Gravity acts without contact and depends on the masses and their separation. In everyday falling objects, air resistance can hide the simple gravitational pattern. Compare shapes and release conditions before assuming a heavier object always has a larger downward acceleration.

A thrown ball also keeps accelerating downward while it is rising. After it leaves the hand, gravity changes its vertical velocity; an initial horizontal velocity continues in an ideal model without drag. The trajectory is the ball’s curved path through space. At its highest point the vertical component of velocity is zero for an instant, while gravity and any horizontal component of velocity are still present. Study the labeled throw below before using the graphs.

Build your understanding

Where this fits

This unit helps answer the chapter question: How can forces explain stability and changes in motion? Keep a notebook table with the question, evidence, explanation and one unresolved issue. Revise a previous model only when you can name the new evidence or idea that changes it.

Part 1 · Distinguish mass from gravitational force

Mass is measured in kilograms and relates to inertia. Weight is the gravitational force on an object, measured in newtons. Near Earth’s surface, the introductory model uses weight=mass×g with g approximately 9.8 N/kg or a supplied rounded value. Different locations can change weight without changing mass.

Two quantities with different units that everyday speech runs together. The kilogram figure is unchanged by location; the newton figure depends on the gravitational field strength where you are.

Read the visual model

What remains unchanged when the same object moves to a weaker gravitational field?

Visual reasoning — after your attempt

Its mass remains the same if no matter is added or lost. Its gravitational weight decreases because the local field is weaker.

A 2 kg object has weight about 19.6 N near Earth using 9.8 N/kg. On a location with weaker gravitational field, the same object retains 2 kg mass but has lower weight. State which quantity a scale reports.

These model gravitational fields produce different weights for the same 2 kg mass. Weight is a force rather than another word for mass. The values are supplied near-surface approximations; the boxes do not show scale, position-dependent fields or a trajectory.

Pause and explain

What remains unchanged when the same object moves to a weaker gravitational field?

Check your reasoning after answering

Its mass remains the same if no matter is added or lost. Its gravitational weight decreases because the local field is weaker.

Part 2 · Explain equal free-fall acceleration

A heavier object experiences a larger gravitational force near Earth, but also has more inertia. In the model neglecting air resistance, these increase together, giving the same acceleration g. Real falling motion may differ because drag depends on shape, size, speed, and surrounding air.

The Apollo 15 crew did this on the Moon with a hammer and a falcon feather, and they landed together. Gravity gives every object the same acceleration; the difference you normally see is air resistance, not weight.

Read the visual model

Why does greater weight not automatically give greater ideal free-fall acceleration?

Visual reasoning — after your attempt

Greater mass also means greater resistance to acceleration. Since gravitational force is mg, force divided by mass gives g for each object when drag is neglected.

A flat sheet and a crumpled sheet of the same paper can fall differently in air despite similar mass. This compares the effect of shape and drag, not a rule that mass alone determines falling speed. Use supplied observations or a low safe drop.

Pause and explain

Why does greater weight not automatically give greater ideal free-fall acceleration?

Check your reasoning after answering

Greater mass also means greater resistance to acceleration. Since gravitational force is mg, force divided by mass gives g for each object when drag is neglected.

Part 3 · Identify what friction opposes

Friction at a contact resists relative slipping or the tendency to slip between surfaces. It can help a walker move forward because a shoe pushes backward against the ground and the ground provides forward static friction. Friction is not always opposite the overall travel direction of an object.

Read the visual model

Can friction help rather than prevent motion?

Visual reasoning — after your attempt

Yes. Static friction between a shoe and ground can provide forward force during walking. Its direction depends on the tendency of the surfaces to slip.

For a sliding box, friction usually acts against its sliding motion relative to the floor. For a driven wheel rolling without slipping, the contact force can have a different direction. Describe the contact motion before assigning the arrow.

Use the two contacts in the figure to test the slogan that friction always opposes motion. The sliding box has friction to the left because it slips right relative to the floor. The planted walking shoe has a tendency to slip backward relative to the ground, so static friction on the shoe can point forward. Static means the surfaces do not slide relative to each other at that contact, not that the entire person is motionless.

Pause and explain

Can friction help rather than prevent motion?

Check your reasoning after answering

Yes. Static friction between a shoe and ground can provide forward force during walking. Its direction depends on the tendency of the surfaces to slip.

Part 4 · Compare resistance with a controlled method

Surface type, normal force, lubrication, and motion conditions can affect friction. A comparison should keep other factors comparable and measure the relevant force or motion. The force needed to start sliding may differ from the force needed to maintain steady sliding. Do not assume one reading applies to every situation.

The supplied sliding-box speeds decrease from 10 to 6 to 2 m/s over two seconds. With right chosen positive and no reversal in this interval, average acceleration is (2−10)/2 = −4 m/s². For a 0.5 kg box this corresponds to a net horizontal force of −2 N. Only if resistance is the sole horizontal force may that net force be identified with friction. Real resistance need not be constant; do not extend this line past stopping to predict backward sliding.

Read the visual model

Why must steady speed be stated when using a pull to estimate friction?

Visual reasoning — after your attempt

At steady straight-line speed the net force is zero, so the pull balances resistance in the stated model. During acceleration the pull need not equal friction.

Pull the same loaded sample at steady speed in supplied trials over two surfaces. Under the stated horizontal balanced-force conditions, the measured pull estimates sliding resistance. A pull during speeding up includes a net force and cannot be interpreted the same way.

Read the sliding-box graph as a motion record, not a picture of its path. The modeled speed falls 4 m/s each second during this interval. If right is positive, acceleration is −4 m/s². For mass 0.5 kg, the net horizontal force is −2 N; call that friction only when there are no other horizontal forces. A straight line here is an illustrative constant-resistance approximation, and must not be continued past the box coming to rest.

Pause and explain

Why must steady speed be stated when using a pull to estimate friction?

Check your reasoning after answering

At steady straight-line speed the net force is zero, so the pull balances resistance in the stated model. During acceleration the pull need not equal friction.

Gravity: masses, distance and free fall

A change of weight with location and a changing gravitational interaction answer related but different questions.

Gravity is an attractive interaction between objects with mass. Attractive means each object is pulled toward the other, with the interaction partner acting on the other receiver. Increasing one mass can increase the interaction; increasing separation generally weakens it for the simple two-object comparison. The evidence table changes one factor at a time. It is not a requirement to memorize a universal gravitation formula or calculate real planetary orbits here.

The two-object records illustrate an attractive interaction that grows with one mass and decreases with separation, keeping other conditions fixed. The symbols M and r label the reference values, not actual measurements of a household object. The graph is evidence for this supplied model comparison, not an orbit calculation.

Near Earth, a falling object can be in free fall when gravity is the only significant force on it. A vacuum is a region with negligible material compared with ordinary air, so an ideal vacuum model removes air drag. Free fall can also be approximated in air when drag is small enough for the question. A heavier object has greater weight and greater inertia; these scale together, giving the same near-Earth acceleration when drag is negligible. A parachute or broad sheet changes drag and is not that simple comparison.

A satellite or a thrown object does not need gravity to vanish while moving. An inward force can continuously change direction, producing a curved path. In a stable simplified orbit, the object does not simply drop straight down because it already has sideways motion. Predicting an exact trajectory needs additional data and a more detailed model. The word stability refers to a persisting pattern under stated conditions, not an absence of forces or all objects being perfectly stationary.

Evidence to interpret

Masses	Separation	Attractive force (relative units)
M and M	r	8
2M and M	r	16
M and M	2r	2

Explain and apply

Use the table to construct a gravitational claim about mass and separation. Then explain why a feather and stone can fall differently in air without proving different ideal free-fall acceleration.

Compare one changed factor at a time.
Explain attraction and appropriate force receivers.
Distinguish gravity-only motion from significant drag.

Reasoning and marking guidance — after your attempt

The force rises from 8 to 16 relative units when one mass doubles at fixed separation, and falls to 2 when separation doubles at the reference masses. These model comparisons support attractive, mass- and distance-dependent interaction under the stated conditions. Feather/stone differences in air also involve drag and inertia; an ideal negligible-drag comparison does not depend on mass in the same way. Separate receivers for the interaction pair and name the model limit.

A thrown ball: trajectory, gravity and graphs

A ball does not need an upward force to keep rising after release. Its existing upward velocity decreases as gravity accelerates it downward. We can connect the curved path to several time graphs without trigonometry.

A trajectory is the path an object follows through space. Break this throw into two simultaneous motions: a horizontal component and a vertical component. A component is the part in one chosen direction. Choose right and up as positive. The model starts at height 0 m with horizontal velocity 6 m/s and upward velocity 10 m/s; gravity gives vertical acceleration −10 m/s². The Earth value is rounded from about 9.8. We ignore air drag and spin and stop the model when the ball returns to its release height.

Think through equal half-second steps. Horizontal velocity stays 6 m/s, so horizontal position increases by 3 m each half-second. Vertical velocity changes by −5 m/s each half-second: +10, +5, 0, −5, −10. Height rises from 0 to 3.75 to 5 m, then falls to 3.75 and 0 m. These are model predictions, not measurements of a real ball. The acceleration does not switch direction at the top, and the hand exerts no continuing force after release.

The physical path has horizontal position on its horizontal axis and height on its vertical axis. The four time graphs instead all have time on the horizontal axis. Their shapes answer different questions. The slope of the horizontal-position graph is horizontal velocity; the slope of the height graph is vertical velocity. The slope of the vertical-velocity graph is vertical acceleration. At 1 s, height is maximum and vertical velocity is zero; horizontal velocity remains 6 m/s and vertical acceleration remains −10 m/s². Do not say that the ball has no velocity or no force at the top.

Read the axes before interpreting the shape. Position-versus-time slope gives the corresponding velocity: horizontal position has a constant positive slope, while height has zero slope at its maximum. The vertical-velocity line crosses zero at 1 s and has constant slope −10 m/s². The horizontal-velocity line has zero slope, meaning zero horizontal acceleration. A curved height–time graph resembles the physical trajectory in this particular constant-horizontal-speed example, but its horizontal axis is time, not position.

For a calculation extension, horizontal position x = 6t, vertical velocity vᵧ = 10−10t, and height y = 10t−5t², with t in seconds and the stated SI units. The symbol t² means t multiplied by itself. At 0.5 s, y = 10×0.5−5×0.25 = 3.75 m. At 1.5 s it is also 3.75 m, but the vertical velocities are opposite. The formulas summarize this ideal constant-acceleration model; they are not a rule for every real throw.

Compare a horizontal throw and a drop from the same height with the same zero initial vertical velocity. Without air drag, their vertical motions match even though one also moves sideways. Both reach the ground together. That conclusion does not compare a drop with a ball launched upward, since those have different initial vertical velocities. Changing only horizontal speed in our explorer changes the range but leaves the 2 s flight time and 5 m maximum height unchanged.

Both balls have the same starting height and zero initial vertical velocity. The horizontal throw has additional horizontal velocity, but in this no-drag model that does not alter vertical acceleration. Their dots at each labeled time are level, and both reach the ground after 1 s for the rounded g = 10 m/s² model. A throw with an upward component would be a different comparison. The drawing omits air resistance, spin and any collision before the ground.

A real ball can experience drag opposite its motion and forces associated with spin. These can change the horizontal velocity, flight time and path. Our simplified model is useful because it isolates what gravity does; predictions must be checked against actual conditions. Two-dimensional motion here extends the one-dimensional motion required in the middle-school standard. Begin with arrows and the table; the algebra is an optional second pass, not a prerequisite for understanding why the ball curves.

Explore the throw

Predict first, then move the time slider. Compare the ball’s position, velocity and acceleration at the same instant. Change horizontal speed to test which parts of the motion change.

The labeled figures and supplied table below contain the complete model; the controls enhance it when JavaScript is available.

Evidence to interpret

Time (s)	Horizontal position (m)	Height (m)	Horizontal velocity (m/s)	Vertical velocity (m/s)	Vertical acceleration (m/s²)
0	0	0	6	+10	−10
0.5	3	3.75	6	+5	−10
1	6	5	6	0	−10
1.5	9	3.75	6	−5	−10
2	12	0	6	−10	−10

Investigate or evaluate the supplied records

Use the supplied no-drag records; predict the velocity and acceleration arrows before checking them. No throwing experiment is required.
Read the axes of each graph and locate the same 0.5 s, 1 s and 1.5 s instants.
Draw a prediction for horizontal speed 2 m/s with upward speed still 10 m/s. Then check the explorer or use x = 2t.
Explain which predictions would be less reliable for a light object experiencing substantial air drag.

Explain and apply

At 0.5 s and 1.5 s the ball has the same height. Explain how its velocity differs while acceleration stays the same. Then predict the flight time, maximum height and horizontal range when only the starting horizontal speed changes from 6 to 2 m/s. Use the figures, graph axes and table in your explanation.

Distinguish trajectory axes from time-graph axes and label velocity and acceleration arrows with directions.
Use the two equal-height records to explain +5 versus −5 m/s vertical velocity and constant −10 m/s² acceleration.
Predict 2 s flight time, 5 m maximum height and 4 m range for 2 m/s horizontal speed, stating the no-drag assumptions.

Reasoning and marking guidance — after your attempt

At 0.5 s the ball is rising with vᵧ = +5 m/s, whereas at 1.5 s it is falling with vᵧ = −5 m/s. Both heights are 3.75 m and horizontal velocity is 6 m/s. In both cases vertical acceleration is −10 m/s², because gravity acts downward throughout. At the top only the vertical velocity becomes zero; a horizontal velocity and downward gravitational force remain. Reducing only horizontal speed to 2 m/s does not change vertical motion: the flight still lasts 2 s, maximum height is 5 m, and range is 2×2 = 4 m. The physical trajectory is height against horizontal position; the four time graphs instead compare each quantity with elapsed time. These predictions assume no drag, the same release and return height, and g rounded to 10 m/s².

Apply the whole unit · Compare gravity and floor resistance

Illustrative case: a 3 kg box is near Earth; use g=10 N/kg. A steady horizontal pull is 8 N on floor A and 12 N on floor B. Ignore other horizontal forces in these trials.

Your task

Calculate weight, draw vertical and horizontal forces for both steady-speed trials, and compare sliding resistance. Explain what this evidence does not tell you about starting friction or ideal falling acceleration.

What your response should show

Use the supplied observations and measurements accurately; include units where needed.
Explain the science behind your answer, rather than giving only a number or label.
Show a labeled model, calculation, or evidence comparison as requested.
State an assumption or limitation and suggest a useful next measurement.

Response guidance — after your attempt

Weight is 30 N downward; on a level floor with no other vertical forces, support is 30 N upward. Steady speed requires net horizontal force zero: resistance is 8 N on A and 12 N on B. Starting friction was not measured. Ideal free-fall acceleration would be g, not greater simply because this box is heavy.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Keep kg and N in separate columns. Ask the learner to label assumptions before inferring friction. Discuss a walking example to prevent the blanket claim that friction always points backward. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation. The illustrated study “Gravity: masses, distance and free fall” is required curriculum content. Teach it before the associated application or distribute it over the assigned unit sessions; it is not an optional enrichment. Its practice/review/quiz response provides evidence of understanding. Model/data work must not be recorded as an actual physical experiment.

The key idea

Weight = mass × g (W = mg) and depends on gravity, while mass never changes; friction always opposes motion between touching surfaces.

Weight

W = mg

m is mass in kg; g is the acceleration due to gravity (9.8 m/s² on Earth); W (weight) comes out in newtons (N).

Worked examples

Example 1

An astronaut has a mass of 70 kg. What is her weight on Earth? (Use g = 9.8 m/s².)

Use W = mg.
W = 70 × 9.8.
= 686.

Answer: 686 N

Example 2 · Worked application

A book rests on a level table. Identify vertical forces and explain why it does not fall.

Earth exerts a downward gravitational force.
The table exerts an upward normal force.
For a stationary book with no other vertical forces, these balance.

Answer: Upward normal force equals downward weight; net vertical force is zero.

Check the reasoning

The book's weight is still present even though it is not falling.

Example 3

The same astronaut's weight on the Moon is about ⅙ of her Earth weight (686 N). What is her approximate weight on the Moon?

Divide her Earth weight by 6.
686 ÷ 6 ≈ 114.3.

Answer: About 114 N

Example 4

Using g≈10 N/kg, find the weight of a 3 kg object and explain why its mass stays the same on the Moon.

Weight near Earth is 3×10=30 N.
A different gravitational field changes force, but not the object's amount of matter or inertia.

Answer: 30 N on Earth; the same 3 kg mass has a smaller weight on the Moon.

Example 5 · Find and fix the mistake

Context: A book rests on a level table. Identify vertical forces and explain why it does not fall. A student claims: “Friction always points opposite an object's overall motion.” Evaluate the claim and write a corrected explanation.

Test the claim against the stated conditions: The book's weight is still present even though it is not falling.
Friction opposes relative slipping or its tendency at a contact. For example, forward static friction can accelerate a rolling driven wheel.

Answer: Friction opposes relative slipping or its tendency at a contact. For example, forward static friction can accelerate a rolling driven wheel.

Check the reasoning

The book's weight is still present even though it is not falling.

Example 6 · Same height, different velocity

For the illustrated throw, compare the ball at 0.5 s and 1.5 s. State height, vertical velocity, horizontal velocity and vertical acceleration.

Read height from the table: both are 3.75 m.
At 0.5 s vertical velocity is +5 m/s; at 1.5 s it is −5 m/s.
Horizontal velocity is 6 m/s at both times.
Vertical acceleration is −10 m/s² throughout the no-drag model.

Answer: Same position height does not imply the same velocity. One ball state rises and the other falls; gravity remains downward.

Check the reasoning

At the top, only the vertical velocity is zero. The downward acceleration does not vanish.

Example 7 · Change the sideways launch

Initial upward speed remains 10 m/s and g remains 10 m/s². Horizontal speed changes from 6 to 10 m/s. Predict time to the top, maximum height, total flight time and range.

Vertical motion is unchanged: top at 1 s and maximum height 5 m.
Return to release height still takes 2 s.
Range = horizontal speed × flight time = 10×2 = 20 m.

Answer: 1 s to top; 5 m maximum height; 2 s flight; 20 m range.

Check the reasoning

These predictions require no drag and returning to the same height; changing upward speed would change vertical motion.

Example 8 · Interpret the visual model

Two quantities with different units that everyday speech runs together. The kilogram figure is unchanged by location; the newton figure depends on the gravitational field strength where you are.

What remains unchanged when the same object moves to a weaker gravitational field?

Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
A 2 kg object has weight about 19.6 N near Earth using 9.8 N/kg. On a location with weaker gravitational field, the same object retains 2 kg mass but has lower weight. State which quantity a scale reports.
Its mass remains the same if no matter is added or lost. Its gravitational weight decreases because the local field is weaker.

Answer: Its mass remains the same if no matter is added or lost. Its gravitational weight decreases because the local field is weaker.

Check the reasoning

Keep the model’s stated limits explicit: Two quantities with different units that everyday speech runs together. The kilogram figure is unchanged by location; the newton figure depends on the gravitational field strength where you are.

Avoid these mistakes

Friction is not always harmful, and mass is not measured in newtons.

Check your understanding

Using g≈10 N/kg, find the weight of a 3 kg object and explain why its mass stays the same on the Moon.

Discuss the answer

30 N on Earth; the same 3 kg mass has a smaller weight on the Moon.

Why are smooth tires poor at transferring a useful force to a wet road?

Discuss the answer

Mass measures inertia and is measured in kilograms. Weight is gravitational force and is measured in newtons. Near Earth's surface weight is approximately mass×9.8 N/kg, although using 10 N/kg is suitable when a question says to approximate. Friction depends on contact materials, surface conditions and the forces pressing surfaces together. It can slow sliding, but it also lets shoes grip the ground and tires push a road. Static friction can act without visible sliding.

Return to the phenomenon

An illustrative 2 kg object has weight 19.6 N using Earth g=9.8 N/kg and 3.2 N using a modeled Moon g=1.6 N/kg. Both trials use the same object. Explain the mass and weight comparison, then identify a friction test that would isolate surface type. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

Mass remains 2 kg, while gravitational force depends on the local gravitational field. Weight equals mass × g, giving the supplied forces. To compare surface friction, match object load, contact procedure, travel direction and measurement, changing only the intended surface. Weight and friction are distinct forces, and air resistance can add another interaction.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

An illustrative 2 kg object has weight 19.6 N using Earth g=9.8 N/kg and 3.2 N using a modeled Moon g=1.6 N/kg. Both trials use the same object. Explain the mass and weight comparison, then identify a friction test that would isolate surface type. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

Use two relevant stated records or conditions.
Explain the mechanism rather than only repeat a definition.
Label observation and inference.
Name a changed model feature or a remaining uncertainty.

Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

Why does the object retain its mass on the Moon? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

Answer the figure question with its stated labels.
Connect the visual representation to the scientific idea.
Identify a specific limitation from the caption.
Propose a useful change without misrepresenting supplied evidence.

Hint

Response guidance — discuss after your attempt

Moving locations changes the gravitational field and weight, not the stated amount of matter. These model gravitational fields produce different weights for the same 2 kg mass. Weight is a force rather than another word for mass. The values are supplied near-surface approximations; the boxes do not show scale, position-dependent fields or a trajectory.

Words to know

gravity: An attractive force between any two objects with mass; bigger masses and closer distances create a stronger pull.
weight: The force of gravity on an object's mass, calculated as weight = mass × g (W = mg).
mass: The amount of matter in an object, measured in kilograms; it doesn't change no matter where the object is.
friction: A force that opposes motion between two surfaces in contact.
air resistance: A type of friction caused by air pushing against a moving object.
model: A representation that explains selected features and makes predictions; it leaves other details out.
evidence: Relevant observations or records used to support or challenge a claim.
system boundary: The chosen limit separating the objects being studied from their surroundings.
assumption: A condition taken as true for a model or calculation and needing to be checked against the case.

Newton's universal law of gravitation: an inverse-square rule

Newton didn't just say gravity exists — he wrote down exactly how it works: F = G(m₁m₂)/r², where m₁ and m₂ are the two objects' masses, r is the distance between their centers, and G is a very small fixed number called the gravitational constant. The 'r²' in the denominator makes this an inverse-square law: double the distance between two objects, and the gravitational force between them drops to one-quarter as strong, not one-half. This is also why gravity between you and a nearby friend is technically real but far too weak to notice — it takes a planet-sized mass for the pull to become obvious.

Henry Cavendish 'weighs the Earth'

Newton's equation includes G, the gravitational constant, but Newton himself never measured its actual value. In 1798 — over a century later — British scientist Henry Cavendish used an extremely sensitive torsion balance (two small lead balls on a thin wire, twisted by the gravitational pull of larger lead spheres) to measure G directly for the first time. Once G was known, scientists could finally calculate Earth's actual mass using nothing but the strength of its gravity at the surface — earning Cavendish's experiment the nickname 'weighing the Earth.'

Static vs. kinetic friction: why the first push is the hardest

Try shoving a heavy couch across a floor and you'll notice something odd: it takes a big effort just to get it moving, but once it's sliding, keeping it moving takes noticeably less force. That's because static friction (between surfaces that aren't yet sliding) is almost always stronger than kinetic friction (between surfaces already in motion) — microscopic surface bumps have to be 'unstuck' from each other before sliding can even begin. This is exactly why cars equipped with anti-lock brakes (ABS) stop faster than cars with locked, skidding tires: rolling tires stay in the stronger static-friction regime, while skidding tires fall into weaker kinetic friction.

The hammer, the feather, and the Moon

In 1971, Apollo 15 commander David Scott performed a now-famous live television demonstration on the airless Moon: he dropped a geologist's hammer and a falcon feather at the same moment, from the same height. With no atmosphere to create air resistance, both hit the lunar surface at exactly the same instant — visual proof of something Galileo had predicted centuries earlier using thought experiments alone. It's a perfect real-world bookend to the feather-and-rock idea from this unit's explanation: gravity accelerates every mass equally, and it's air resistance alone (not gravity) that normally makes light, spread-out objects fall more slowly on Earth.

In the real world

Engineers design tire treads to increase friction with the road, helping cars brake safely, especially in the rain.

Exit check

Why does the object retain its mass on the Moon? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Problem 1

Find the weight of a 50 kg student on Earth. Use g = 9.8 m/s² and W = mg.

Answer and explanation

490 N

W = mg = 50 × 9.8 = 490 N.

Problem 2

A rock has a mass of 12 kg. What is its weight on Earth? (g = 9.8 m/s²)

Answer and explanation

117.6 N

W = mg = 12 × 9.8 = 117.6 N.

Problem 3

Which stays the same no matter where in the universe an object is?

its weight
its mass
the pull of gravity on it
none of these

Answer and explanation

its mass

Mass is the amount of matter in an object and doesn't change with location, unlike weight.

Problem 4

Which surface pairing would create the MOST friction?

ice on ice
rubber on dry pavement
oiled metal on metal
polished wood on polished wood

Answer and explanation

rubber on dry pavement

Rough, grippy surfaces like rubber on dry pavement create much more friction than smooth or lubricated ones.

Problem 5

Explain why a feather falls slower than a rock through air, even though gravity pulls on both.

Answer and explanation

Air resistance pushes up on the feather much more relative to its weight, because of its large surface area and very low mass, which slows its fall a lot. In a vacuum with no air resistance, a feather and a rock would actually fall at the same rate.

Problem 6

An object weighs 98 N on Earth. Using W = mg with g = 9.8 m/s², find its mass.

Answer and explanation

10 kg

m = W ÷ g = 98 ÷ 9.8 = 10 kg.

Problem 7

Using g≈10 N/kg, find the weight of a 3 kg object and explain why its mass stays the same on the Moon. Explain the reasoning in your own words.

Answer and explanation

30 N on Earth; the same 3 kg mass has a smaller weight on the Moon.

Weight near Earth is 3×10=30 N.

A different gravitational field changes force, but not the object's amount of matter or inertia.

Response criteria

Use the stated conditions.
Show the evidence or calculation.
Explain the conclusion and any stated limitation.

Problem 8

A box slides right across a rough floor. State the direction of kinetic friction from the floor. Show the reasoning, not just the conclusion.

Hints

The book's weight is still present even though it is not falling.

Answer and explanation

Left, opposing the box's sliding relative to the floor.

Problem 9

An object of mass 3 kg has weight 30 N in a simplified g=10 N/kg model. Would its mass change on the Moon?

Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

Mass remains 3 kg; weight changes with the local gravitational field.

Problem 10

Use the table to construct a gravitational claim about mass and separation. Then explain why a feather and stone can fall differently in air without proving different ideal free-fall acceleration.

Hints

Use the illustrated study titled Gravity: masses, distance and free fall. Keep the observations, model and conditions separate.

Answer and explanation

Response criteria

Compare one changed factor at a time.
Explain attraction and appropriate force receivers.
Distinguish gravity-only motion from significant drag.

Problem 11

In the no-drag throw with initial horizontal velocity 6 m/s, what are horizontal velocity, vertical velocity and vertical acceleration at the top? Does gravity stop acting?

Answer and explanation

Horizontal velocity 6 m/s; vertical velocity 0; vertical acceleration −10 m/s². Gravity continues acting downward.

Separate the two velocity components.

Distinguish zero vertical velocity from zero acceleration.

Response criteria

State all three values with units.
Keep gravity downward.
Avoid claiming zero total velocity.

Problem 12

Keep upward launch speed 10 m/s and g = 10 m/s². Change only horizontal speed to 2 m/s. Predict flight time, maximum height and range back to release height.

Answer and explanation

2 s; 5 m; 4 m respectively, in the same no-drag model.

Vertical motion is unchanged.

Range = 2 m/s × 2 s = 4 m.

Response criteria

Keep flight time and height unchanged.
Calculate range with units.
State no drag and same return height.

Problem 13

Two balls start 5 m above the ground with zero vertical velocity; one is dropped and the other launched horizontally. In a no-drag model, which lands first? Would adding an upward launch component keep this comparison the same?

Answer and explanation

They land together (after 1 s using g = 10 m/s²). An upward component changes initial vertical velocity, so the original comparison no longer applies.

Horizontal motion does not change the shared vertical acceleration.

Distinguish horizontal from upward launch.

Response criteria

Use equal-height and vertical-velocity conditions.
State the no-drag limit.
Explain why an upward throw is different.

Problem 14

Two quantities with different units that everyday speech runs together. The kilogram figure is unchanged by location; the newton figure depends on the gravitational field strength where you are.

For this unit’s illustrated case, what remains unchanged when the same object moves to a weaker gravitational field?

Answer and explanation

Its mass remains the same if no matter is added or lost. Its gravitational weight decreases because the local field is weaker.

Response criteria

Use the named labels, directions or supplied quantities accurately.
Connect the visual evidence to the scientific mechanism or calculation.
State the relevant model conditions or limitation.

Problem 15

For a no-drag ball launched upward at 8 m/s and horizontally at 3 m/s, use g = 10 m/s². At 0.8 s state both velocity components and acceleration, then predict horizontal range when it returns to release height.

Answer and explanation

At the top after 0.8 s: horizontal velocity 3 m/s, vertical velocity 0, vertical acceleration −10 m/s². Total flight is 1.6 s, so range is 4.8 m under the same-height ideal model.

Vertical velocity loses 10 m/s each second, reaching zero after 0.8 s.

Symmetric ideal same-height return takes twice that time; multiply by horizontal speed.

At the top after 0.8 s: horizontal velocity 3 m/s, vertical velocity 0, vertical acceleration −10 m/s². Total flight is 1.6 s, so range is 4.8 m under the same-height ideal model.

Response criteria

Use the named labels, directions or supplied quantities accurately.
Connect the visual evidence to the scientific mechanism or calculation.
State the relevant model conditions or limitation.

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