Calculus I · Adding Up the Infinite

Problems

Six tiers. Fluency and Practice are doing* — build Riemann sums and find antiderivatives until both are automatic (and like Chapter 4, there’s a lot of antiderivative drill, because it’s the same kind of mechanical skill). Concept & counterexample and ◆ Diamond are thinking — signed area, the +C+C, and the proofs. Teach it is teaching. Looking ahead opens Chapter 11. Do all of Fluency; antiderivative fluency is what makes the Fundamental Theorem usable.*

Fluency — do these fast

  1. Antiderivatives, reverse power rule: (a) ∫x4dx\int x^4\,dx; (b) ∫x7dx\int x^7\,dx; (c) ∫x−2dx\int x^{-2}\,dx; (d) ∫xdx\int \sqrt{x}\,dx; (e) ∫1dx\int 1\,dx.
  2. With constants and sums: (a) ∫(3x2−2x+5)dx\int (3x^2 - 2x + 5)\,dx; (b) ∫(6x5+4)dx\int (6x^5 + 4)\,dx; (c) ∫(1x2+x)dx\int \left(\tfrac1{x^2} + x\right)dx.
  3. Trig and exponential antiderivatives: (a) ∫cos⁡xdx\int \cos x\,dx; (b) ∫sin⁡xdx\int \sin x\,dx; (c) ∫exdx\int e^x\,dx; (d) ∫sec⁡2xdx\int \sec^2 x\,dx; (e) ∫1xdx\int \tfrac1x\,dx.
  4. Mixed library: (a) ∫(2cos⁡x−3sin⁡x)dx\int (2\cos x - 3\sin x)\,dx; (b) ∫(ex+x2)dx\int (e^x + x^2)\,dx; (c) ∫(4sec⁡2x−5x)dx\int (4\sec^2 x - \tfrac5x)\,dx.
  5. Rewrite first, then integrate: (a) ∫x2−1xdx\int \tfrac{x^2 - 1}{x}\,dx (split the fraction); (b) ∫x2xdx\int x^2\sqrt{x}\,dx (one power); (c) ∫(x+1)2dx\int (x+1)^2\,dx (expand).
  6. Simple substitution (the inside’s derivative is present): (a) ∫2x(x2+1)5dx\int 2x(x^2+1)^5\,dx; (b) ∫3x2(x3+1)4dx\int 3x^2(x^3+1)^4\,dx; (c) ∫cos⁡xesin⁡xdx\int \cos x\,e^{\sin x}\,dx; (d) ∫4x3(x4+2)6dx\int 4x^3(x^4+2)^6\,dx; (e) ∫sin⁡4xcos⁡xdx\int \sin^4 x\cos x\,dx.
  7. Substitution needing a constant factor, or landing on a log: (a) ∫xex2dx\int x\,e^{x^2}\,dx; (b) ∫x(x2+1)3dx\int x(x^2+1)^3\,dx; (c) ∫sin⁡(3x)dx\int \sin(3x)\,dx; (d) ∫cos⁡(5x)dx\int \cos(5x)\,dx; (e) ∫x2x3+1dx\int \dfrac{x^2}{x^3+1}\,dx (the logarithm pattern).
  8. Estimate ∫04fdx\int_0^4 f\,dx for f(x)=x2f(x) = x^2 with a right Riemann sum using n=4n = 4 rectangles (widths of 11). Is your estimate above or below the true area, and why?
  9. Evaluate by recognizing the area as a simple shape: (a) ∫032dx\int_0^3 2\,dx (a rectangle); (b) ∫02xdx\int_0^2 x\,dx (a triangle); (c) ∫−11xdx\int_{-1}^{1} x\,dx (watch the sign).

Practice — multi-step

  1. Compute ∫01x3dx\int_0^1 x^3\,dx from the definition, using ∑i=1ni3=[n(n+1)2]2\sum_{i=1}^n i^3 = \left[\tfrac{n(n+1)}{2}\right]^2 and a right Riemann sum. (Mirror the ∫01x2\int_0^1 x^2 computation in the chapter.)
  2. Substitution: (a) ∫2xx2+1dx\int \dfrac{2x}{x^2+1}\,dx; (b) ∫xx2+9dx\int \dfrac{x}{\sqrt{x^2+9}}\,dx; (c) ∫sin⁡xcos⁡xdx\int \sin x\cos x\,dx (let u=sin⁡xu=\sin x).
  3. Substitution with rearrangement: (a) ∫ln⁡xxdx\int \dfrac{\ln x}{x}\,dx (let u=ln⁡xu = \ln x); (b) ∫xx+1dx\int x\sqrt{x+1}\,dx (let u=x+1u = x+1, then write x=u−1x = u-1).
  4. Find the function FF with F′(x)=3x2−2F'(x) = 3x^2 - 2 and F(1)=5F(1) = 5. (Antiderivative, then pin down CC from the condition — your first “initial value problem.”)
  5. A ball’s velocity is v(t)=−10t+20v(t) = -10t + 20 (m/s). Find its position s(t)s(t) given s(0)=0s(0) = 0, by antidifferentiating. (You’re undoing the Chapter 3 derivative that produced vv from ss.)
  6. Set up — but do not yet evaluate — the area under f(x)=e−x2f(x) = e^{-x^2} from 00 to 11 as a limit of Riemann sums, and explain why you cannot finish it by finding an antiderivative.
  7. Sketch f(x)=x2−1f(x) = x^2 - 1 on [0,2][0,2] and explain, using signed area, why ∫02(x2−1)dx\int_0^2 (x^2-1)\,dx is smaller than the unsigned area between the curve and the axis.

Concept & counterexample — think; true/false with justification, or build the example

    1. ∫abfdx\int_a^b f\,dx is a number; ∫fdx\int f\,dx is a function. (b) If F′=G′F' = G', then F=GF = G. (c) ∫abfdx\int_a^b f\,dx can be negative even when ff is a “real” function. (d) Every continuous function has an antiderivative that can be written with elementary functions.
  1. Why the +C+C? Explain, citing the Mean Value Theorem, why two antiderivatives of the same function must differ by a constant — and why this means ∫fdx\int f\,dx is a whole family.
  2. Find the error. A student writes ∫sin⁡xdx=cos⁡x+C\int \sin x\,dx = \cos x + C. What’s wrong, and how would differentiating the answer have caught it?
  3. Construct a function ff on [−1,1][-1,1] whose definite integral ∫−11fdx\int_{-1}^1 f\,dx is 00 even though ff is never zero. (Use signed area — what symmetry forces cancellation?)
  4. Explain when substitution will and won’t help: why does it work for ∫2x(x2+1)5dx\int 2x(x^2+1)^5\,dx but not, as written, for ∫(x2+1)5dx\int (x^2+1)^5\,dx? What’s missing in the second?
  5. Is it possible? A definite integral ∫abfdx\int_a^b f\,dx that equals 00 with a<ba < b and f>0f > 0 somewhere on [a,b][a,b]. (What must ff do elsewhere?)

◆ Diamond — the definitions and the proofs

  1. ◆ Compute ∫01x2dx\int_0^1 x^2\,dx from the definition in full, deriving the limit of the right Riemann sum and using ∑i2=n(n+1)(2n+1)6\sum i^2 = \tfrac{n(n+1)(2n+1)}{6}. (Reproduce the chapter’s computation, justifying each step.)
  2. ◆ Prove the linearity of the definite integral, ∫ab(f+g)=∫abf+∫abg\int_a^b (f+g) = \int_a^b f + \int_a^b g, from the Riemann-sum definition. (A sum of sums is the sum of the sums; take the limit.)
  3. ◆ Derive substitution from the chain rule. Starting from ddxF(g(x))=F′(g(x))g′(x)\tfrac{d}{dx}F(g(x)) = F'(g(x))g'(x), integrate both sides to obtain the substitution rule ∫F′(g(x))g′(x)dx=F(g(x))+C\int F'(g(x))g'(x)\,dx = F(g(x)) + C, and explain why it is exactly the chain rule read backward.
  4. ◆ Prove that a function with F′(x)=0F'(x) = 0 for all xx on an interval is constant there (the fact behind the +C+C). (This is a one-line corollary of the Mean Value Theorem — state it.)
  5. ◆◆ The midpoint sum is sharp. For f(x)=x2f(x) = x^2 on [0,1][0,1], compute the midpoint Riemann sum with nn rectangles and show it also converges to 13\tfrac13 — but, by comparing to the right sum, argue that it approaches the true value faster. (You’ll need ∑(i−12)2\sum (i - \tfrac12)^2.)
  6. ◆◆ Explain why ∫abfdx\int_a^b f\,dx being defined as a limit means it can fail to exist for badly behaved ff (for instance, a function that jumps infinitely often). What property of ff — met by every continuous function — guarantees the Riemann sums actually converge? (Name it; the proof is a real-analysis matter.)

Teach it — explain it, write it up, or fix it

  1. In three or four sentences with the rectangles picture, teach a friend why the area under a curve is a limit of sums, and how thinner rectangles make the estimate exact.
  2. Debug your classmate. They compute ∫2x(x2+1)5dx=(x2+1)66⋅2x+C\int 2x(x^2+1)^5\,dx = \tfrac{(x^2+1)^6}{6} \cdot 2x + C — they “kept the 2x2x.” Explain where their substitution went wrong and give the correct answer.
  3. Write a complete worked solution to ∫xex2dx\int x\,e^{x^2}\,dx, narrating the choice of uu, the handling of the stray constant, and the back-substitution, so a peer could redo it for ∫xsin⁡(x2)dx\int x\sin(x^2)\,dx.
  4. Design a problem. Invent an integral that requires a substitution, choose it so the answer is clean, and write the full solution key (including the differentiate-to-check step).
  5. In a few sentences, teach the difference between the definite integral (a number, an area) and the indefinite integral (a family of functions), and why they nonetheless share a symbol.

Looking ahead — Chapter 11, the summit, in your hands early

  1. Define A(x)=∫0xt2dtA(x) = \int_0^x t^2\,dt — the area under t2t^2 from 00 out to a movable right edge xx. Using your result ∫01t2dt=13\int_0^1 t^2\,dt = \tfrac13, guess a formula for A(x)A(x), then compute A′(x)A'(x). What do you notice about A′(x)A'(x) compared to the integrand t2t^2? (You are about to discover the Fundamental Theorem yourself.)
  2. If finding the area under ff amounts to finding an antiderivative FF and looking at its endpoint values, predict the formula for ∫abfdx\int_a^b f\,dx in terms of F(a)F(a) and F(b)F(b). (Chapter 11 proves your guess and turns every area problem into a subtraction.)
  3. The one antiderivative that escaped the power rule was ∫1xdx=ln⁡|x|\int \tfrac1x\,dx = \ln|x|. Predict what the function L(x)=∫1x1tdtL(x) = \int_1^x \tfrac1t\,dt has to do with the logarithm — in particular, what is L(1)L(1), and is LL increasing or decreasing for x>1x > 1? (Chapter 11 defines ln\ln this way and repays every loan from Chapter 5.)

Questions to talk about

No answer key. These are for arguing over, with someone who read the same chapter.

  1. The integral has two faces that look unrelated: area under a curve, and the reverse of differentiation. The chapter develops both and deliberately leaves them staring across a gap. Why build the suspense rather than resolve it immediately?
  2. Some perfectly ordinary functions have no antiderivative you can write down at all. Does that mean the area under them does not exist, or something else?
  3. Both the derivative and the integral are built by the same move: approximate, then take the limit. What does it suggest that the two great engines of calculus are the same trick pointed in opposite directions?

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